What I mean by this equation is: x^3-2x^(x-2.5)+x^(x^x)
You can remove parenthesis or bracket by multiplying the number outside, with the number inside the bracket.
3/2(1-5)=-6 3/2(-4)=-6 3/-8=-6 Not equal. This equation is a false equation. Unless a variable was meant to be in the equation, this equation is not equal.
Multiply
the equation is 5(a+2) if a is 1 than the answer is 15 if a is 2 than the answer is 20 if a is 3 than the answer is 25 etc...
What I mean by this equation is: x^3-2x^(x-2.5)+x^(x^x)
You can remove parenthesis or bracket by multiplying the number outside, with the number inside the bracket.
Parentheses is when you are doing an equation, and you solve the problem.
3/2(1-5)=-6 3/2(-4)=-6 3/-8=-6 Not equal. This equation is a false equation. Unless a variable was meant to be in the equation, this equation is not equal.
the [ and ] brackets are for if you need an equation like [(9+1)+5] so if you need parenthesis in another parenthesis that is what its for and so is { and }
Multiply
(a^2+7a-8)/(a^2+6a-7) (original equation) (a+8)(a-1)/(a+7)(a-1) (simplify top and bottom) (a+8)/(a+7) <--answer
the equation is 5(a+2) if a is 1 than the answer is 15 if a is 2 than the answer is 20 if a is 3 than the answer is 25 etc...
I believe you mean parenthesis..well it is when you use ( ) puntuation together and as a pair make up what is known to be parenthesis.
a=64 b=8 (x+16x+64)=(x+8)^2
Yes, when there are parenthesis in an equation, you have to use the distibutive property.
If the slope of the given equation is 1/5 then the slope of the parallel equation will be the same which works out as: y-8 = 1/5(x-3) => y = 1/5x+7.4