Na+ plus OH- plus H+ equals H2O plus Na+ plus Cl-
P + Na(OH) + H20 = NaH2PO2 + PH3
Sodium (Na) has been reduced.
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The binding of Na+ ions to the pump
Na+ plus OH- plus H+ equals H2O plus Na+ plus Cl-
P + Na(OH) + H20 = NaH2PO2 + PH3
Na+ and Cl- are spectator ions.
The net ionic equation for the given reaction is H+ (aq) + OH- (aq) → H2O (l)
The reaction of Na (sodium) with H2O (water) produces NaOH (sodium hydroxide) and H2 (hydrogen gas). So, the equation would be 2Na + 2H2O → 2NaOH + H2.
Hydrochloric acid and sodium hydroxide yield salt and water H+ + Cl- + Na+ + OH- --> Na+ + Cl- + H2OComment:In solutions you better leave unchanged ions ( Cl- and Na+) out of the balanced equation: called to be 'tribune ions' (people on the tribune don't take part in the 'match'):H+ + OH- --> H2O This looks simpler than: H+ + Cl - + Na + + OH- --> Na + + Cl - + H2O
Sodium chloride is dissociated in water: NaCl------------------Na+ + Cl-
2Na + 2H2O -> H2 + 2NaOH
Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) -> H2O(l) + Na+(aq) + Cl-(aq)
2Na + 2H2O -------> 2NaOH + H2
NaHCO3 + H2O = H2CO3 +OH + Na
Sodium (Na) has been reduced.