2NaH2 + O2 yields 2Na + 2H2O
Na+ plus OH- plus H+ equals H2O plus Na+ plus Cl-
P + Na(OH) + H20 = NaH2PO2 + PH3
Sodium (Na) has been reduced.
In the reaction involving Na⁺, OH⁻, Cl⁻, and H₂O, the spectator ions are Na⁺ and Cl⁻. These ions do not participate in the chemical reaction; they remain unchanged in the solution. The key species that participate in the reaction are OH⁻ and H₂O, which can combine to form water or other products depending on the context.
In the reaction given, the spectator ions are the ions that do not participate in the actual chemical change. In this case, the Na⁺ ions remain unchanged on both sides of the equation, so they are the spectator ions. The OH⁻ and H⁺ ions combine to form water (H₂O), while the Cr species is also involved in the reaction, potentially forming a compound.
Na+ plus OH- plus H+ equals H2O plus Na+ plus Cl-
P + Na(OH) + H20 = NaH2PO2 + PH3
Na+ and Cl- are spectator ions.
The net ionic equation for the given reaction is H+ (aq) + OH- (aq) → H2O (l)
The reaction of Na (sodium) with H2O (water) produces NaOH (sodium hydroxide) and H2 (hydrogen gas). So, the equation would be 2Na + 2H2O → 2NaOH + H2.
Hydrochloric acid and sodium hydroxide yield salt and water H+ + Cl- + Na+ + OH- --> Na+ + Cl- + H2OComment:In solutions you better leave unchanged ions ( Cl- and Na+) out of the balanced equation: called to be 'tribune ions' (people on the tribune don't take part in the 'match'):H+ + OH- --> H2O This looks simpler than: H+ + Cl - + Na + + OH- --> Na + + Cl - + H2O
Sodium chloride is dissociated in water: NaCl------------------Na+ + Cl-
2Na + 2H2O -> H2 + 2NaOH
Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) -> H2O(l) + Na+(aq) + Cl-(aq)
2Na + 2H2O -------> 2NaOH + H2
NaHCO3 + H2O = H2CO3 +OH + Na
Sodium (Na) has been reduced.