x + 7y = 33 (Eqn 1) 3x + 2y = 7 (Eqn 2) Multiply Eqn 1 by 3, now the equations are 3x + 21y = 99 (Eqn 3) 3x + 2y = 7 (Eqn 2) Subtract Eqn 2 from Eqn 4 and the result of subtraction is 19y = 92 Hence y = 92/19 Now substitute the value of y in Eqn 1 x + (7) x (92/19) = 33 x = 33 - 644/19 = -(17/19)
Eqn (A): => 2x + 5y = 16 Eqn (B): => 5x + 2y = -2 5*Eqn (A) - 2*Eqn (B): 21y = 84 => y = 4 Substituting for y in Eqn (a): x = -2
Eqn 1: x - 2y = 3 Eqn 2: 5x + 3y = 2 5 times Eqn 1: 5x - 10y = 15 Eqn 2 - 5*Eqn 1: 0x + 13y = -13 so that 13y = -13 or y = -1 Substitute in Eqn 1: x + 2*1 = 3 x + 2 = 3 x = 1 Solution: x = 1, y = -1
c - 5d = 2 2c + d = 4 Multiply eqn 1 by 2: 2c - 10d = 4 Subtract this from eqn 2: 0c + 11d = 0 which implies that d = 0 Then, by eqn 1, c = 2
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x + 7y = 33 (Eqn 1) 3x + 2y = 7 (Eqn 2) Multiply Eqn 1 by 3, now the equations are 3x + 21y = 99 (Eqn 3) 3x + 2y = 7 (Eqn 2) Subtract Eqn 2 from Eqn 4 and the result of subtraction is 19y = 92 Hence y = 92/19 Now substitute the value of y in Eqn 1 x + (7) x (92/19) = 33 x = 33 - 644/19 = -(17/19)
Eqn (A): => 2x + 5y = 16 Eqn (B): => 5x + 2y = -2 5*Eqn (A) - 2*Eqn (B): 21y = 84 => y = 4 Substituting for y in Eqn (a): x = -2
Eqn 1: x - 2y = 3 Eqn 2: 5x + 3y = 2 5 times Eqn 1: 5x - 10y = 15 Eqn 2 - 5*Eqn 1: 0x + 13y = -13 so that 13y = -13 or y = -1 Substitute in Eqn 1: x + 2*1 = 3 x + 2 = 3 x = 1 Solution: x = 1, y = -1
First lets look at the equation for a circle... (x - h)2 + (y - k)2 = r2 What do I know? The center must be constant so H and K are two variables I need to solve for... and I know I need to solve for R as well! take your points (i'm making a simple circle with center (0,0) with radius of 1...) 1,0 0,1 -1,0 I have my 3 points.... I will make myself 3 equations: eqn #1a: (1 - h)2 +(0 - k)2 = r2 eqn #2a: (0 - h)2 +(1 - k)2 = r2 eqn #3a: (-1 - h)2 +(0 - k)2 = r2 Ok so now I have some equations to play with... eqn #1b: h2 - 2h +1 + k2 = r2 eqn #2b: h2 + k2-2k +1 = r2 eqn #3b: h2 + 2h +1 + k2= r2 The rest is subsitution... We want r's value so lets see. Lets take eqn #1b and #2b... h2 - 2h +1 + k2 = h2 + k2-2k +1 Balance it out cancle and such try to make it = 0 - 2h = -2k h = k so now I know I can replace h with k or k with h It doesn't matter which one I make to the other if we had 2h = k I would put 2h in its just simpler... keep in mind either way works. eqn #1c: k2 - 2k +1 + k2 = r2 eqn #2c: k2 + k2-2k +1 = r2 eqn #3c: k2 + 2k +1 + k2= r2 collect terms eqn #1c: 2k2 - 2k +1 = r2 eqn 1 is the same as eqn 2! eqn #2c: 2k2 - 2k +1 = r2 eqn #3c: 2k2 + 2k +1= r2 We really have two equations left now it doesn't always work out this way. Set eqn 2 and 3 equal to each other via the r 2k2 - 2k +1 = 2k2 + 2k +1 do some cancling -2k = 2k at this point I know k = 0 its the only viable answer.... take any one of our origonal equations.... h2 - 2h +1 + k2 = r2 all the parts with k or h = 0; remember h = k = 0 1 = r2 1 = r If I had time I would do a more complex equation for yea... but this kinda gets the point across...
Photosynthesis equation: 6CO2 + 6H2O + light energy -> C6H12O6 + 6O2 Cellular respiration equation: C6H12O6 + 6O2 -> 6CO2 + 6H2O + ATP
Vert is green.
Juan Vert's birth name is Juan Vert Carbonell.
Vert Ramp=a halfpipe with a vert on the top edge of both sides of it to enable the rider to catch air. (vert)icalQuarterpipe=1/2 of a vert ramp or halfpipe
6x - 5y = 11 --------- Eqn 1 -4x + 7y = 11 ------- Eqn 2 ___________ 24x - 20y = 44 ------ Eqn 1 multiplied by 4 on both sides, equation won't change -24x + 42y = 66 ---- Eqn 2 multiplied by 6 on both sides, equation won't change _____________ 0x + 22y = 110 ----- Adding the two eqns above gives you this result _____________ That is 22y = 110, or y = 5 (Answer) Now substitute the value of y in either eqn 1 or eqn 2 (we will use eqn 1) 6x - 5(5) = 11 6x = 11 + 25 = 36 x = 6 (Answer)
Vert means "green" in French.
Vert means turn
uzi vert is a rapper