x + 7y = 33 (Eqn 1)
3x + 2y = 7 (Eqn 2)
Multiply Eqn 1 by 3, now the equations are
3x + 21y = 99 (Eqn 3)
3x + 2y = 7 (Eqn 2)
Subtract Eqn 2 from Eqn 4 and the result of subtraction is
19y = 92
Hence y = 92/19
Now substitute the value of y in Eqn 1
x + (7) x (92/19) = 33
x = 33 - 644/19 = -(17/19)
Chat with our AI personalities
3x + 2y = 7
(2, -1)
3x-2y-7=0
3x+2y = 1 2y = -3x+1 y = -1.5x+0.5
3x+2y=6 2y=-3x+6 y=-1.5x+3
-3x + 2y = 9 2y = 3x + 9y = 1,5x + 4,5
3x + 2y = 7
The ordered pair is (5, 4).
(2, -1)
3x-2y-7=0
3x = 2y + 7 The standard form is: 3x - 2y - 7 = 0
3x+2y = 1 2y = -3x+1 y = -1.5x+0.5
3x+2y=6 2y=-3x+6 y=-1.5x+3
3x+2y=9 2y=9-3x y=-1.5x-4.5
x = 5 and y = 4
3x+2y-5=0 3x+2y=5 Im lost im only 12 work out the rest hope i helped
3x + 2y = 8 This is an equation. It could be the equation of a line.