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x + 7y = 33 (Eqn 1)

3x + 2y = 7 (Eqn 2)

Multiply Eqn 1 by 3, now the equations are

3x + 21y = 99 (Eqn 3)

3x + 2y = 7 (Eqn 2)

Subtract Eqn 2 from Eqn 4 and the result of subtraction is

19y = 92

Hence y = 92/19

Now substitute the value of y in Eqn 1

x + (7) x (92/19) = 33

x = 33 - 644/19 = -(17/19)

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13y ago

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