'X' can have any value, from negative infinity to positive infinity.
As far as you've told us in the question, there's no connection
between 'x' and the coins.
To find the number of outcomes for flipping 4 coins, you can use the expression (2^n), where (n) is the number of coins. In this case, since (n = 4), the expression becomes (2^4). This simplifies to 16, meaning there are 16 possible outcomes when flipping 4 coins.
1 in 4
When flipping two coins, each coin has two possible outcomes: heads (H) or tails (T). The total number of outcomes when flipping two coins is 2 × 2 = 4, which includes HH, HT, TH, and TT. Out of these four outcomes, only one results in both coins landing on tails (TT). Therefore, the probability of both coins landing on tails is 1 out of 4, or 25%.
The probability of getting all tails when you flip 4 fair coins 1 time is:P(4 tails) = (1/2)4 = 1/16 = 0.0625 = 6.25%
Well, you have 24 possibilities, and you can get heads 6 ways, so it is 1/4.
To find the number of outcomes for flipping 4 coins, you can use the expression (2^n), where (n) is the number of coins. In this case, since (n = 4), the expression becomes (2^4). This simplifies to 16, meaning there are 16 possible outcomes when flipping 4 coins.
If they are fair coins, the probability is 0.25
1/4
1 in 4
When flipping two coins, each coin has two possible outcomes: heads (H) or tails (T). The total number of outcomes when flipping two coins is 2 × 2 = 4, which includes HH, HT, TH, and TT. Out of these four outcomes, only one results in both coins landing on tails (TT). Therefore, the probability of both coins landing on tails is 1 out of 4, or 25%.
When flipping a coin, there are 2 possible outcomes. When flipping 3 coins there are 8 possible outcomes (2^3=8). As for the situation described, there is only one way for it to not be true, if all the coins land on the same side. So either all heads or all tails. This leaves 8-2=6 possible outcomes resulting in the above situation. Therefore the probability of the given situation is 6/8 or 3/4=75%
75% is not correct. The odds of flipping 4 independent coins is the same as flipping one coin 4 times. The number of outcomes of 4 flips is 2^4 or 16. The number of ways to exactly get 3 Heads is 4 (THHH, HTHH, HHTH, HHHT) so your chance of flipping 3 heas is 4/16 or 25%. If you include the occurance that produced 4 of 4 Heads, then you get 5/16 or 31.25%.
The probability of getting all tails when you flip 4 fair coins 1 time is:P(4 tails) = (1/2)4 = 1/16 = 0.0625 = 6.25%
Well, you have 24 possibilities, and you can get heads 6 ways, so it is 1/4.
HH, HT, TH, or TT. Each has a probability of 1/4. You might consider HT and TH the same, in which case you'd say the probably of HH and TT are 1/4 each and the probability of TH is 1/2.
You are in Australia - maybe - and have 4 coins of 50 cents each.
There are 2*4*6 = 48 possible outcomes in total.