HH, HT, TH, or TT. Each has a probability of 1/4. You might consider HT and TH the same, in which case you'd say the probably of HH and TT are 1/4 each and the probability of TH is 1/2.
When flipping a coin, there are 2 possible outcomes. When flipping 3 coins there are 8 possible outcomes (2^3=8). As for the situation described, there is only one way for it to not be true, if all the coins land on the same side. So either all heads or all tails. This leaves 8-2=6 possible outcomes resulting in the above situation. Therefore the probability of the given situation is 6/8 or 3/4=75%
There are 2^10 = 1024 of them.
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12.
There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12.
When flipping 3 coins, each coin has 2 possible outcomes: heads (H) or tails (T). Therefore, the total number of outcomes is calculated as (2^3), which equals 8. The possible outcomes are: HHH, HHT, HTH, HTT, THH, THT, TTH, and TTT. Thus, there are 8 different outcomes from flipping 3 coins.
When flipping a coin, there are two possible outcomes: heads (H) or tails (T). If you flip one coin, there are 2 outcomes. If you flip multiple coins, the total number of outcomes is calculated as (2^n), where (n) is the number of coins flipped. For example, flipping 3 coins results in (2^3 = 8) possible outcomes.
To find the number of outcomes for flipping 4 coins, you can use the expression (2^n), where (n) is the number of coins. In this case, since (n = 4), the expression becomes (2^4). This simplifies to 16, meaning there are 16 possible outcomes when flipping 4 coins.
16
When flipping a coin, there are 2 possible outcomes. When flipping 3 coins there are 8 possible outcomes (2^3=8). As for the situation described, there is only one way for it to not be true, if all the coins land on the same side. So either all heads or all tails. This leaves 8-2=6 possible outcomes resulting in the above situation. Therefore the probability of the given situation is 6/8 or 3/4=75%
When flipping a quarter, a nickel, and a dime, each coin has two possible outcomes: heads (H) or tails (T). Since there are three coins, the total number of possible outcomes is calculated as (2^3), which equals 8. Therefore, there are 8 possible outcomes when flipping a quarter, a nickel, and a dime once.
There are 2^10 = 1024 of them.
When flipping two coins, each coin has two possible outcomes: heads (H) or tails (T). The total number of outcomes when flipping two coins is 2 × 2 = 4, which includes HH, HT, TH, and TT. Out of these four outcomes, only one results in both coins landing on tails (TT). Therefore, the probability of both coins landing on tails is 1 out of 4, or 25%.
When flipping a coin 8 times, each flip has 2 possible outcomes: heads or tails. Therefore, the total number of possible outcomes is calculated by raising the number of outcomes for one flip to the power of the number of flips: (2^8). This equals 256 possible outcomes.
When flipping two coins, each coin has two possible outcomes: heads (H) or tails (T). The total possible outcomes for two coins are HH, HT, TH, and TT, making four outcomes in total. The combinations that result in one coin showing heads and the other tails are HT and TH, giving us 2 favorable outcomes. Therefore, the probability of getting one head and one tail is 2 out of 4, or 1/2 (50%).
There are two outcomes for each coin and three coins; 2 x 2 x 2 = 23 = 8 outcomes.
For each of the coins, in order, you have two possible outcomes so that there are 2*2*2*2 = 16 outcomes in all.