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To find the roots of the equation (-x^2 - 4x + 12 = 0), we can first rewrite it as (x^2 + 4x - 12 = 0). Using the quadratic formula (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}) with (a = 1), (b = 4), and (c = -12), we calculate the discriminant: (b^2 - 4ac = 16 + 48 = 64). Thus, the roots are (x = \frac{-4 \pm 8}{2}), giving us (x = 2) and (x = -6).

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6d ago

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