To find the roots of the equation (-x^2 - 4x + 12 = 0), we can first rewrite it as (x^2 + 4x - 12 = 0). Using the quadratic formula (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}) with (a = 1), (b = 4), and (c = -12), we calculate the discriminant: (b^2 - 4ac = 16 + 48 = 64). Thus, the roots are (x = \frac{-4 \pm 8}{2}), giving us (x = 2) and (x = -6).
It is a quadratic equation in X, with two real roots.
-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12
The expression (x^2 + 8x + 12) is a quadratic equation. It can be factored into ((x + 6)(x + 2)). This indicates that the solutions (or roots) of the equation (x^2 + 8x + 12 = 0) are (x = -6) and (x = -2).
(x-2)(x+12) = 0 x = 2 or x -12
Yes. 3a plus 12 plus 6 is an example of an Equation.
It is a quadratic equation in X, with two real roots.
-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12
The expression (x^2 + 8x + 12) is a quadratic equation. It can be factored into ((x + 6)(x + 2)). This indicates that the solutions (or roots) of the equation (x^2 + 8x + 12 = 0) are (x = -6) and (x = -2).
(x-2)(x+12) = 0 x = 2 or x -12
Yes. 3a plus 12 plus 6 is an example of an Equation.
1 + 12 is not an equation.
No. 3a 12 plus a 6 is not a solution Of an equation.
Use the quadratic equation: x = (-b plusminus root(b2 - 4ac)) / 2aIn this case, a = 1, b = 9, c = 12.Another answer:x2+9x+12 = 0When factorised by means of the quadratic equation formula:(x+7.372281323)(x+1.627718677) = 0Therefore the roots are: -7.372281323 and -1.627718677Check that your answer is correct by multiplying out the brackets which should bring you back to x2+9x+12 = 0
The equation is y + 2 = 12.
The equation seems to equal 72.
The equation -7 plus 12 equals out to be five. This is a math problem.
Without an "equals" somewhere along the way, you only have an expression, not an equation.Without an equation, there is no question, and nothing to answer.