The expression (x^2 + 8x + 12) is a quadratic equation. It can be factored into ((x + 6)(x + 2)). This indicates that the solutions (or roots) of the equation (x^2 + 8x + 12 = 0) are (x = -6) and (x = -2).
(x - 6)(x - 2)
x + 5
If: x^2 -8x = -12 then x^2-8x+12 = 0 and so x = 2 or x = 6
p(x) = x4 + 2x3 + x2 + 8x - 12When you go to graph this function, you make 'y' = p(x) .At the y-intercept, 'x' is zero.There, y = -12 .
2x2 + 11x + 12 = 2x2 + 3x + 8x + 12 = x*(2x + 3) + 4*(2x + 3) = (2x + 3)*(x + 4)
x^(2) - 8x + 12 Write down all the pairs of factors of '12'. They are ( 1,12) , ( 2, 6) , ( 3 ,4). Select a pair that add to '8' . Viz, ( 2,6). Set up brackets ( x 6)(x 2) Which signs???? Since '12' is positive (+), then both the signs are the same. Since '8' is negative(-), then both signs are negative. Hence ( x - 6)(x - 2) Fully factored . Done!!!!!!
(x - 6)(x - 2)
x + 3
x + 5
If: x^2 -8x = -12 then x^2-8x+12 = 0 and so x = 2 or x = 6
X2 - 8X + 15 = (X - 3)(X - 5)
(x+4)(x+4), or (x+4)^2.
x^2 +8x -9 is equivalent to (x+9)(x-1) when factored
(x + 4)(x +4) or (x + 4)squared
2(x + 3)(x + 1)
p(x) = x4 + 2x3 + x2 + 8x - 12When you go to graph this function, you make 'y' = p(x) .At the y-intercept, 'x' is zero.There, y = -12 .
2x2 + 11x + 12 = 2x2 + 3x + 8x + 12 = x*(2x + 3) + 4*(2x + 3) = (2x + 3)*(x + 4)