We need to use the quadratic formula for this.
-b±√(b2-4ac)
-----------------
2a
Let me explain some of the symbols and letters first.
±- is the plus or minus sign. You will perform both separately when we reach this step.
√-is the square root sign.
The line above 2a is the division line.
The letter a represents the quantity of x2, which is 1 in this case
The letter b represents the quantity of x, which is 5 in this case
The letter c represents the quantity of 1, which is 11 in this case
Let's plug the numbers in.
-5±√(52-4(1)(11))
-----------------
2(1)
Solve:
-5±√(52-4(1)(11))
----------------------- =
2(1)
-5±√((25)-(44))
----------------------- =
2
-5±√((25)-(44))
----------------------- =
2
-5±√(-19)
----------------------- =
2
We cannot have a square root of a negative, so this polynomial is not able to be solved if we restrict ourselves to the real numbers. However, we certainly have two complex roots.
To find the roots of the polynomial (x^2 + 5x + 9), we can use the quadratic formula: (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}). Here, (a = 1), (b = 5), and (c = 9). The discriminant (b^2 - 4ac = 5^2 - 4 \cdot 1 \cdot 9 = 25 - 36 = -11), which is negative. This means the polynomial has no real roots, but two complex roots: (x = \frac{-5 \pm i\sqrt{11}}{2}).
It is a quadratic polynomial.
-5x + 729
7X^3 Third degree polynomial.
2x+5x-24 7x2-24
None, it involves the square root of a negative number so the roots are imaginary.
-2.5 + 1.6583123951777i-2.5 - 1.6583123951777i
There are none because the discriminant of the given quadratic expression is less than zero.
To find the roots of the polynomial (x^2 + 5x + 9), we can use the quadratic formula: (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}). Here, (a = 1), (b = 5), and (c = 9). The discriminant (b^2 - 4ac = 5^2 - 4 \cdot 1 \cdot 9 = 25 - 36 = -11), which is negative. This means the polynomial has no real roots, but two complex roots: (x = \frac{-5 \pm i\sqrt{11}}{2}).
It is a quadratic polynomial.
-5x + 729
7X^3 Third degree polynomial.
x = -2.5 + 1.6583123951777ix = -2.5 - 1.6583123951777iwhere i is the square root of negative one.
yes, and it is 14x
2x+5x-24 7x2-24
To find the degree of the polynomial ( 7x^7 + 10x^4 + 4x^3 - 5x^{11} - 10x^6 - 6x^7 ), we identify the term with the highest exponent. The terms are ( 7x^7 ), ( 10x^4 ), ( 4x^3 ), ( -5x^{11} ), ( -10x^6 ), and ( -6x^7 ). The term with the highest exponent is ( -5x^{11} ), which has a degree of 11. Therefore, the degree of the polynomial is 11.
5x(3x+4)