0
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Enter the degree of the polynomial below 6x6 plus 9x3 plus 3x2 - 4x10 - 9x5 - 5x6?
10
The polynomial below is a perfect square trinomial of the form A2 - 2AB plus B2 9x2-18x plus 36?
TrUE
The polynomial below is a perfect square trinomial of the form A2 - 2AB plus B2 4x2-16x plus 16?
True
What value of c makes the polynomial below a perfect square trinomial 4x2-32x plus c?
64
What is the degree of this polynomial 3x2 - 4x plus 9?
The degree of this polynomial is 2.
Which two values of x are roots of the polynomial below x2 plus 5x plus 11?
There are none because the discriminant of the given quadratic expression is less than zero.
Which two values of x are roots of the polynomial x2 plus 5x plus 9?
-2.5 + 1.6583123951777i-2.5 - 1.6583123951777i
What 2 values of x are roots of the polynomial x2 plus 3x-5?
You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).
The polynomial 32 plus 4x plus 3 has how many roots?
1
X2-11x plus 13 has two values of x are roots of a polynomial what is it?
x=11+69/2 and x=11-69/2
What is the sum of the roots of the polynomial shown below f(x)3x3 plus 12x2 plus 3x-18?
To find the sum of the roots of the polynomial ( f(x) = 3x^3 + 12x^2 + 3x - 18 ), we can use Vieta's formulas. The sum of the roots of a cubic polynomial ( ax^3 + bx^2 + cx + d ) is given by ( -b/a ). Here, ( a = 3 ) and ( b = 12 ), so the sum of the roots is ( -\frac{12}{3} = -4 ).
If the factors of a polynomial are x plus 2 and x plus 6 what values of x make that polynomial 0?
-2 and -6
What are the roots of the polynomial x2 plus 3x plus 5?
You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).
The polynomial 4x2 plus 5x plus 4 has how many roots?
None, it involves the square root of a negative number so the roots are imaginary.
Which two values of x are roots of the polynomial of x2 plus 5x plus 9?
To find the roots of the polynomial (x^2 + 5x + 9), we can use the quadratic formula: (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}). Here, (a = 1), (b = 5), and (c = 9). The discriminant (b^2 - 4ac = 5^2 - 4 \cdot 1 \cdot 9 = 25 - 36 = -11), which is negative. This means the polynomial has no real roots, but two complex roots: (x = \frac{-5 \pm i\sqrt{11}}{2}).
If the factors of a polynomial are x plus 4 and x plus 8 what values of x make that polynomial 0?
-6 Check: -6+4-6+8 = 0
Which two values of x are roots of the polynomial below 3x2-3x 1?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals". There is no sign (plus or minus) before the final 1.
