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s1 = 21 in s2 = 2s3 - 3 in s2 + s3 > s1 2s3 - 3 + s3 > 21 3s3 - 3 > 21 3s3 > 24 s3 > 8 s2 - s3 < s1 2s3 - 3 - s3 < 21 s3 - 3 < 21 s3 < 24 So that, 8 < s3 < 24, and 2(8) - 3 < s2 < 2(24) - 3 13 < s2 < 45
The area of a square is s2, where s is the measurement of one side. A = 132 = 169cm2.
The area of a square is the square of its side, so the answer is (s-4)2, which is s2 - 8s + 16.
If s represents the length of one side, the area is s * s or s2.
s1 = side 1 s2 = side 2 and H = Hypotenuses12 + s22 = H2therefore H = square-root of (s12 + s22)