To find the solutions of the equation (2x^2 + 8x + 26 = 0), we can use the quadratic formula (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}), where (a = 2), (b = 8), and (c = 26). First, we calculate the discriminant: (b^2 - 4ac = 8^2 - 4(2)(26) = 64 - 208 = -144). Since the discriminant is negative, the equation has no real solutions, but two complex solutions given by (x = -4 \pm 6i).
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
26
To find the number of solutions to the equation (8x + 11 = 8x + 8), we can simplify it by subtracting (8x) from both sides, resulting in (11 = 8). This is a false statement, indicating that there are no values of (x) that can satisfy the equation. Therefore, there are zero solutions to this equation.
2x2 + 11x + 12 = 2x2 + 3x + 8x + 12 = x*(2x + 3) + 4*(2x + 3) = (2x + 3)*(x + 4)
2x2 = 8x x = 8x/2x x = 4 Check: 2(4)2 = 8(4) 2(16) = 32 32 = 32
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
26
To find the number of solutions to the equation (8x + 11 = 8x + 8), we can simplify it by subtracting (8x) from both sides, resulting in (11 = 8). This is a false statement, indicating that there are no values of (x) that can satisfy the equation. Therefore, there are zero solutions to this equation.
2x2 + 11x + 12 = 2x2 + 3x + 8x + 12 = x*(2x + 3) + 4*(2x + 3) = (2x + 3)*(x + 4)
2x2 = 8x x = 8x/2x x = 4 Check: 2(4)2 = 8(4) 2(16) = 32 32 = 32
Do you mean 2x²? Assuming this is the case: 2x² - 3x + 8x - 12 = 2x² + 5x - 12 = (2x - 3)(x + 4)
That equation has no solutions.There's no number that can go in place of 'x' that canmake the equation a true statement.
-3.........
-4
2 this Domo
y=-2x^2+8x+3
-1/2