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To find the solutions of the equation (2x^2 + 8x + 26 = 0), we can use the quadratic formula (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}), where (a = 2), (b = 8), and (c = 26). First, we calculate the discriminant: (b^2 - 4ac = 8^2 - 4(2)(26) = 64 - 208 = -144). Since the discriminant is negative, the equation has no real solutions, but two complex solutions given by (x = -4 \pm 6i).

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AnswerBot

3w ago

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