x-2 = 3 is the single point x = 5. Not quite sure of the point in graphing a single value of a single variable!
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the graph is moved down 6 units
There are none. For this equation, there is nonreal answer, as the graph of the quadratic does not pass below the x-axis
There are no real solutions to this equation because you cannot take the square root of a negative number. However,x2 + 4 = 0x2 = -4sqrt(x2) = sqrt(-4)x = 2i, -2ihere are the imaginary solutions.
x2≤64
It will have two solutions because its a quadratic equation: x = -8.472135955 or x = 0.472135955