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What are the solutions for 3x2 -9x?
To find the solutions for the equation (3x^2 - 9x = 0), we can factor it as (3x(x - 3) = 0). Setting each factor equal to zero gives us the solutions: (3x = 0) or (x - 3 = 0). Thus, the solutions are (x = 0) and (x = 3).
Parentheses before -1 and after 3x and before 3 and after 3x What is the answer to -2 cos2 3x-3 sin 3x equals 0?
I think you mean to solve:(-2 cos23x) - (3 sin 3x) = 0cos2 x + sin2 x = 1⇒ cos2x = 1 - sin2 x⇒ -2 cos2 3x - 3 sin 3x = -2(1 - sin2 3x) - 3 sin 3x = 0⇒ 2 sin2 3x - 3 sin 3x - 2 = 0⇒ (2 sin 3x + 1)(sin 3x - 2) = 0⇒ sin 3x = -1/2 or 2sin 3x = 2 is impossible as the range of sine is -1 ≤ sine ≤ 1Thus:sin 3x = -1/2⇒ 3x = 2nπ - π/6 or 2nπ - 5π/6⇒ x = 2/3nπ -π/18 or 2/3nπ -5π/18
How do you solve 3x - 16 equals 2?
3X - 16 = 2 add 16 to both sides 3X - 16 + 16 = 2 + 16 3X = 18 divide both sides integers by 3 (3/3)X = 18/3 X = 6 ----------------check in original equation 3(6) - 16 = 2 18 - 16 = 2 2 = 2 -------------checks
X-3x-6 divided by 6 equals3x plus 2 divided by 3?
(x - 3x - 6) / 6 = (3x + 2) / 3 ∴3x - 9x - 18 = 18x + 12 ∴3x - 9x - 18x = 12 - 18 ∴-24x = -6 ∴ x = 1/4
If 3x-1 equals 11 what is the value of x2 plus 2?
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
What are the solutions to 3x^2-x+5=0?
no real solutions
What does x equals in 3x 12 equals 18?
3x+12 = 18 3x = 18-12 3x = 6 x = 2
What are the solutions for 3x2 -9x?
To find the solutions for the equation (3x^2 - 9x = 0), we can factor it as (3x(x - 3) = 0). Setting each factor equal to zero gives us the solutions: (3x = 0) or (x - 3 = 0). Thus, the solutions are (x = 0) and (x = 3).
How many values of x and y satisfy the equations 2x plus 6y equals 12 and 3x plus 9y equals 18?
2X + 6Y = 12 3X + 9Y = 18 try elimination - 3(2X + 6Y = 12) 2(3X + 9Y = 18) - 6X - 18Y = - 36 6X + 18Y = 36 ================= I will say this system is dependent and an infinite number of solutions can be found.
Parentheses before -1 and after 3x and before 3 and after 3x What is the answer to -2 cos2 3x-3 sin 3x equals 0?
I think you mean to solve:(-2 cos23x) - (3 sin 3x) = 0cos2 x + sin2 x = 1⇒ cos2x = 1 - sin2 x⇒ -2 cos2 3x - 3 sin 3x = -2(1 - sin2 3x) - 3 sin 3x = 0⇒ 2 sin2 3x - 3 sin 3x - 2 = 0⇒ (2 sin 3x + 1)(sin 3x - 2) = 0⇒ sin 3x = -1/2 or 2sin 3x = 2 is impossible as the range of sine is -1 ≤ sine ≤ 1Thus:sin 3x = -1/2⇒ 3x = 2nπ - π/6 or 2nπ - 5π/6⇒ x = 2/3nπ -π/18 or 2/3nπ -5π/18
How do you solve 3x - 16 equals 2?
3X - 16 = 2 add 16 to both sides 3X - 16 + 16 = 2 + 16 3X = 18 divide both sides integers by 3 (3/3)X = 18/3 X = 6 ----------------check in original equation 3(6) - 16 = 2 18 - 16 = 2 2 = 2 -------------checks
X-3x-6 divided by 6 equals3x plus 2 divided by 3?
(x - 3x - 6) / 6 = (3x + 2) / 3 ∴3x - 9x - 18 = 18x + 12 ∴3x - 9x - 18x = 12 - 18 ∴-24x = -6 ∴ x = 1/4
How many solutions are there to the equation below 3x - 10(x plus 2) 13 - 7x?
How many solutions are there to the equation below? 3x-10(x+2) = 13-7x 0
Y = 3x 2?
5
X2 plus 3x - 18 equals 0?
x^2+3x-18=0 (x+6)(x-3)=0
If 3x-1 equals 11 what is the value of x2 plus 2?
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
How do you solve 3 x plus 2 equals x-18?
3x + 2 = x - 18 - 2 = - 2 3x = x - 20 - x = - x 2x = -20 /2 = /2 x = -10
