Not being an equation, it does not have a "solution" per se.
If you wish to factor it, you can do it like so:
x2 + 20 - 9x
= x2 - 5x - 4x + 20
= x(x - 5) - 4(x - 5)
= (x - 4)(x - 5)
If that expression is equal to zero, then x would be equal to 4 or 5.
i thinking this answer should be -20
A binomial
x2 + 9 + 20 = x2 + 29, and can not be factored.I assume though that you mis-wrote your question, and what you in fact want to ask is how to factor x2 + 9x + 20.In that case, the answer is (x + 4)(x + 5).
This quadratic equation has no solutions because its discriminant is less than zero.
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
i thinking this answer should be -20
A binomial
It is (x+4)(x+5) when factored
x2 + 9 + 20 = x2 + 29, and can not be factored.I assume though that you mis-wrote your question, and what you in fact want to ask is how to factor x2 + 9x + 20.In that case, the answer is (x + 4)(x + 5).
This quadratic equation has no solutions because its discriminant is less than zero.
x - 4. x^2 + 5x - 36 = (x - 4) (x + 9) x^2 - 9x + 20 = (x - 4) (x - 5)
x2-9x+18 = (x-3)(x-6) when factorised
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
x2 - 9x + 18 = (x - 3)(x - 6)
x2+9x+18 find factors of 18 that add up to 9, in this case 6&3 (x+6)(x+3)
x2 + 9x + 20 = 0 ∴(x + 4)(x + 5) = 0 ∴x ∈ {-5, -4}