i thinking this answer should be -20
A binomial
This quadratic equation has no solutions because its discriminant is less than zero.
x2 + 9 + 20 = x2 + 29, and can not be factored.I assume though that you mis-wrote your question, and what you in fact want to ask is how to factor x2 + 9x + 20.In that case, the answer is (x + 4)(x + 5).
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
i thinking this answer should be -20
A binomial
It is (x+4)(x+5) when factored
This quadratic equation has no solutions because its discriminant is less than zero.
x2 + 9 + 20 = x2 + 29, and can not be factored.I assume though that you mis-wrote your question, and what you in fact want to ask is how to factor x2 + 9x + 20.In that case, the answer is (x + 4)(x + 5).
x - 4. x^2 + 5x - 36 = (x - 4) (x + 9) x^2 - 9x + 20 = (x - 4) (x - 5)
x2-9x+18 = (x-3)(x-6) when factorised
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
x2 - 9x + 18 = (x - 3)(x - 6)
x2 + 9x + 20 = 0 ∴(x + 4)(x + 5) = 0 ∴x ∈ {-5, -4}
If you mean: x2+9x+20 then it is (x+4)(x+5) = 0 when factored