I also need to know the answer to this problem. Can anyone answer it?
(5x - 2)(x - 5)
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
3x2 + 27x +60
9xy(3xy - 4)
the answer is (3x-2)(9x squared+6x+4)
(8x + 9)(3x^2 - 1)
I also need to know the answer to this problem. Can anyone answer it?
(5x - 2)(x - 5)
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
3x2 + 27x +60
9xy(3xy - 4)
19
In order to factor the sum of the cubes, we need to use this form a³ + b³ = (a + b)(a² - ab + b²). Let a³ = 27x³ and b³ = 343y³. Then, a = 3x and b = 7y. Perform substitution of these terms for the form, and we obtain: 27x3 + 343y3 = (3x + 7y)(9x2 - 21xy + 49y2)
(2x - 3)(x - 12)
It is: 23-27x when simplified
27x2 - 90x + 27 = 9*(3x - 1)*(x - 3)