What are the steps to get y2 plus 4y-12 equals 0?

Answer 1

y2 + 4y -12 = 0

y2 + 6y - 2y -12 = 0

y(y + 6) -2(y +6) = 0

(y -2) x (y + 6) = 0

Hence (y-2) is zero which gives y = 2

or (y + 6) is zero which gives y = -6

The roots or solutions to the equation y2 + 4y -12 = 0 are y = 2 and y = -6