186
Two ways to solve:183/3= 61. So 61 is in the middle, and your other two numbers would be 60, and 62.The other way is algebraically. x+(x+1)+(x+2)=183 x is your starting number, and consecutive numbers would just be x+1, and x+2. Solve, to get the first number of 60, then just get 61 and 62.Final answer: 60, 61, 62.
3X61=183
One hundred eighty three.
1, 2, 3, 122, 183 and 366.
186
2: 183 and 184.
IF they are three consecutive numbers then the lowest number can be represented with "X" The next consecutive number is 1 greater than the 1 b4 so it must be "x+1" The last consecutive number must be 1 more, so it is "x+2" If they are the sum that you can set up the equation: X + X + 1 + X + 2 = 183 3x +3 = 183 3x = 180 x = 60 Naw you can just substitute for X. then answer should be 60,61, and 62
Two ways to solve:183/3= 61. So 61 is in the middle, and your other two numbers would be 60, and 62.The other way is algebraically. x+(x+1)+(x+2)=183 x is your starting number, and consecutive numbers would just be x+1, and x+2. Solve, to get the first number of 60, then just get 61 and 62.Final answer: 60, 61, 62.
The page numbers would be 183 and 184.
(x)+(x+1)+(x+2)=183 3x-3=183-3 3x=180 _______ 3 x=60 x+2=61 x+3=62
The square root of 183 is between 13 and 14.
3X61=183
183 can be divided by these numbers: 1, 3, 61, 183
183
Divide the sum of the three consecutive odd integers by 3: 183/3 = 61. The smallest of these integers will be two less than 61 and the largest will be two more than 61, so the three consecutive odd integers will be 59, 61, 63.
It is 183*184/2 = 16836