72/3 = 24 and 7+8+9 = 24 so the integers are 7, 8 and 9.
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
The sum is 3*(x-1) or 3x - 3
1+8+0 = 9 or 180+80+0 = 260
I'm assuming this is supposed to say: "What are three consecutive integers that add together to equal 171?"This could also be "What are three consecutive integers that multiply together to equal 171?"I will do both.For the addition caseThink of "three consecutive integers" as the expressions x, x+1, and x+2. For any value of x, these three expressions will give that number, the number that is one greater than it, and the number that is two greater than it. So, the expression x+(x+1)+(x+2) is the general sum of three consecutive integers. Also possible is the expression x+(x-1)+(x-2), which are still three consecutive integers. So, this is a simple equation:x+(x+1)+(x+2)=171x+x+1+x+2=1713x+3=1713x=168x=168/3x=56Since x=56, x+1=57 and x+2=58So the three numbers are 56,57,and 58You can check this answer by adding the three numbers together. I'll bet they equal 171.For the multiplication case:Refer to the explanation for the addition case, but instead of the end expression being x+(x+1)+(x+2), it is now the multiplication of the three integers, meaning the expression is (x)(x+1)(x+2), so we get: (x)(x+1)(x+2)=171(x)(x2+3x+2)=171x3+3x2+2x=171I'll admit right now I don't know a simple way to solve this equation, which hints to me that addition was the intent of the question, but this equation can be solved by plotting the equationsy=x3+3x2+2xy=171and finding their point(s) of intersection. The value comes out to be approximately 4.6106, which means that the numbers 4.6106, 5.6106, and 6.6106 will multiply to equal approximately 171 (but not exactly). No exact answer is really possible here.
There is no set of three consecutive integers for 187.
Divide the sum of the three consecutive odd integers by 3: 183/3 = 61. The smallest of these integers will be two less than 61 and the largest will be two more than 61, so the three consecutive odd integers will be 59, 61, 63.
Three consecutive integers have a sum of 12. What is the greatest of these integers?
The square root of 183 is between 13 and 14.
IF they are three consecutive numbers then the lowest number can be represented with "X" The next consecutive number is 1 greater than the 1 b4 so it must be "x+1" The last consecutive number must be 1 more, so it is "x+2" If they are the sum that you can set up the equation: X + X + 1 + X + 2 = 183 3x +3 = 183 3x = 180 x = 60 Naw you can just substitute for X. then answer should be 60,61, and 62
There is no set of three consecutive integers for 106.
There is no set of three consecutive integers whose sum is 71.
The sum of three consecutive integers is -72
9240 is the product of the three consecutive integers 20, 21, and 22.
The sum of the squares of the three consecutive integers 11, 13, 15 = 515
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
Find 2 consecutive ODD integers whose sum is -88 ANSWER: -45, -43