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What is the difference between the multiplication rule for independent versus dependent events?
Given two events, A and B, Pr(A and B) = Pr(A)*Pr(B) if A and B are independent and Pr(A and B) = Pr(A | B)*Pr(B) if they are not.
What is the probability of obtaining exactly three heads in four flips of a coin given that at least two are heads?
Pr(3H given >= 2H) = Pr(3H and >= 2H)/Pr(>=2H) = Pr(3H)/Pr(>=2H) = (1/4)/(11/16) = 4/11.
What is the probability of rolling two fair value dice getting two different numbers?
Pr(Two different numbers) = 1 - Pr(Two same) = 1 - 1/6 = 5/6 = 83.3%
What is the describing of the complementary event and find its probability?
Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).
What is the probability when two people alternately are picking first from a class with 12 girls and 13 boys and then from a class with 10 boys and 11 girls that the first will pick two girls first?
The fact that the two people are picking alternately first from one class and then from the second means that the first picker always has first selection from whoever is remaining in each class; thus for the first picker: pr(1st girl) = 12/(12+13) = 12/25 Pr(2nd girl) = 11/(11+10) = 11/21 → Pr(two girls picked) = pr(1st girl) × pr(2nd girl) = 12/25×11/21 = 44/175
When was Grayling - PR firm - created?
Grayling - PR firm - was created in 1981.
How much does it cost for a pr firm?
It depends upon the PR Firm totally.
What is Grayling PR firm 's population?
The population of Grayling - PR firm - is 1,000.
What actors and actresses appeared in The PR Firm - 2009?
The cast of The PR Firm - 2009 includes: Matt Drappel as The Dictator Joe Lofranco as The PR Guy
What is a PR firm?
A PR Firm also known as a Public Relations Firm is company which helps any Business or any individual to build and maintain an image. It also helps businesses to handle and solve many issues and crisis with its professional strategies.
Who is the pr for demi lovato?
The public relation firm for Demi Lovato is the Berri Goldfarb Public Relations firm
How do you start a pr firm?
Any person with education background in Mass Media and PR can open a PR business. Its a highly challenging feild which requires sheer passion, hard work, and creativity.
What is the best PR firm?
There are many PR Firms which are good, it depends on the kind of business requirement. You can check with Genesis BM India. They are one of the leading and fastest growing PR firms in India and worldwide.
Which Oscar-winning actress was dropped by her PR firm this month?
Two-time Academy Award winner Hilary Swark parted ways with her publicity firm 42 West after it was revealed that she attended an October 2011 birthday function for the controversial dictator of Chechnya.
What is the difference between the multiplication rule for independent versus dependent events?
Given two events, A and B, Pr(A and B) = Pr(A)*Pr(B) if A and B are independent and Pr(A and B) = Pr(A | B)*Pr(B) if they are not.
If you roll one die with 6 sides what is the probability that you will roll a 3 or a 4?
The answer is 1/3. There are six possible outcomes (1 to 6) of which two (3 or 4) are favourable so the probability is 2/6 or 1/3. In general, if A and B are two events, then Pr (A or B) = Pr(A) + Pr(B0 - Pr(A and B) [the last bit is because you are double counting those events] Here Pr(A) = Pr(3) = 1/6, Pr(B) = Pr(4) = 1/6 and Pr(A and B) = Pr(3 and 4 - simultaneously) = 0 So Pr(3 or 4) = 1/6 + 1/6 + 0 = 1/3
What is the probability of obtaining exactly three heads in four flips of a coin given that at least two are heads?
Pr(3H given >= 2H) = Pr(3H and >= 2H)/Pr(>=2H) = Pr(3H)/Pr(>=2H) = (1/4)/(11/16) = 4/11.
