2 an 96
As a product of its prime factors in exponents: 25*3 = 96
To find the HCF of two numbers you first need to write them as the product of their prime factors: 52 = 2x2x13 96 = 2x2x2x2x2x3 The next step is to identify any common prime factors. In this case, both numbers have two 2s as prime factors. Multiply these and you get: 2x2 = 4 Thus the HCF of 52 and 96 is 4.
In terms of exponents: 25*3 = 96
the two numbers that go into 96 are i dont know lol
2 an 96
29950795999/pi
8*12 = 96
As a product of its prime factors in exponents: 25*3 = 96
2 and 3
No, they are not relatively prime.
To find the HCF of two numbers you first need to write them as the product of their prime factors: 52 = 2x2x13 96 = 2x2x2x2x2x3 The next step is to identify any common prime factors. In this case, both numbers have two 2s as prime factors. Multiply these and you get: 2x2 = 4 Thus the HCF of 52 and 96 is 4.
96 = 2x2x2x2x2x3
In terms of exponents: 25*3 = 96
They are: 90 91 92 93 94 95 and 96 which are between the prime numbers of 89 and 97
106
They are not prime numbers because they have other factors aside from 1 and themselves.