Let 2n be the first integer, then the next on is 2n+2 and the one after is 2n+4 so adding all three we have 6n+6=108 or 6n=102 and we want 2n so divide we divide 6n by 3 and we have 2n=34, and 2n+2=36 and lastly 2n+4=38 so 34, 36, 38 are the even integers we seek.
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3 consecutive even integers whose sum is 396 are 130, 132 and 134.
The integers are -16 and -14.
14,16.18
The integers are 6, 8 and 10.
-2, -4, -6