45/3-1, 45/3 and 45/3+1
that is, 14, 15 and 16.
43, 44, 45
13 + 15 + 17 = 45.
-14,-15,-16.
The numbers are 41, 43 and 45.
45, 46, 47, 48 = 186
13,15,17
43, 44, 45
13 + 15 + 17 = 45.
Divide the sum of the three consecutive odd integers by 3: 45/3 = 15. The smallest of these integers will be two less than 15 and the largest will be two more than 15, so the three consecutive odd integers will be 13, 15, and 17.
-14,-15,-16.
13+15+17=45
Divide the sum of the three consecutive integers by 3: 138/3 = 46. The smallest of these integers will be one less than 46 and the largest will be one more than 46, so the three consecutive integers will be 45, 46, and 47.
The numbers are 41, 43 and 45.
45, 46, 47, 48 = 186
Those three odd integers are 43, 45, and 47.
Those three odd integers are 43, 45, and 47.
Let's call the three consecutive integers x, x+1, and x+2. The sum of these integers is x + (x+1) + (x+2) = 3x + 3. We know that this sum is equal to 135, so we can set up the equation 3x + 3 = 135. Solving for x gives us x = 44. Therefore, the three consecutive integers are 44, 45, and 46.