33, 34, 35, 36
Let the first lowest number be x, then x + x + 1 + x + 2 + x + 3 = 138 4x + 6 = 138 4x = 138 - 6 4x = 132 x = 33 and the number are 33, 34, 35, and 36, add them and you will get 138
The numbers are -48, -46 and -44 AND -47, -46, and -45. ( all negative numbers can be either odd or even)
gcf of 138 and 207 is 69.
69 + 69 = 138.
136 + 138+ 140
The integers are 44, 46 and 48.
The simplest way is to solve 4n + 6 = 138 for the smallest of them.
33, 34, 35, 36
138 is, itself, an integer. It is impossible for any integer to lie between two consecutive integers.
Do-it-in-your-head method: The middle number MUST be a third of the total so 138 divided by 3 is 46, making your three numbers 44, 46 and 48. Shazam!
45, 46 and 47.
The numbers are 45, 46 and 47.
The three consecutive even numbers with a sum of 138 are 44, 46 and 48.
Let the first lowest number be x, then x + x + 1 + x + 2 + x + 3 = 138 4x + 6 = 138 4x = 138 - 6 4x = 132 x = 33 and the number are 33, 34, 35, and 36, add them and you will get 138
I assume you mean what are the two consecutive integers. Algebraically; X = integers.X + (X + 1) = 2752X + 1 = 2752X = 274X = 137============solution setorSince the consecutive integers differ by 1, then the first number is 274/2 = 137, so the second one is 1 more, 138.
The equation to solve this is... x + (x + 2) + (x + 4) = 138 x + x + x + 2 + 4 = 138 3x + 6 = 138 3x = 132 x = 44 x = 44 x + 2 = 46 x + 4 = 48 So, the three consecutive even numbers that add up to 138 are... 44, 46, & 48