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Divide the sum of the three consecutive integers by 3: 138/3 = 46. The smallest of these integers will be one less than 46 and the largest will be one more than 46, so the three consecutive integers will be 45, 46, and 47.

Q: Find three consecutive integers with the sum of 138?

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33, 34, 35, 36

Let the first lowest number be x, then x + x + 1 + x + 2 + x + 3 = 138 4x + 6 = 138 4x = 138 - 6 4x = 132 x = 33 and the number are 33, 34, 35, and 36, add them and you will get 138

The numbers are -48, -46 and -44 AND -47, -46, and -45. ( all negative numbers can be either odd or even)

gcf of 138 and 207 is 69.

69 + 69 = 138.

Related questions

136 + 138+ 140

The integers are 44, 46 and 48.

The simplest way is to solve 4n + 6 = 138 for the smallest of them.

33, 34, 35, 36

138 is, itself, an integer. It is impossible for any integer to lie between two consecutive integers.

Do-it-in-your-head method: The middle number MUST be a third of the total so 138 divided by 3 is 46, making your three numbers 44, 46 and 48. Shazam!

45, 46 and 47.

The numbers are 45, 46 and 47.

The three consecutive even numbers with a sum of 138 are 44, 46 and 48.

Let the first lowest number be x, then x + x + 1 + x + 2 + x + 3 = 138 4x + 6 = 138 4x = 138 - 6 4x = 132 x = 33 and the number are 33, 34, 35, and 36, add them and you will get 138

I assume you mean what are the two consecutive integers. Algebraically; X = integers.X + (X + 1) = 2752X + 1 = 2752X = 274X = 137============solution setorSince the consecutive integers differ by 1, then the first number is 274/2 = 137, so the second one is 1 more, 138.

The equation to solve this is... x + (x + 2) + (x + 4) = 138 x + x + x + 2 + 4 = 138 3x + 6 = 138 3x = 132 x = 44 x = 44 x + 2 = 46 x + 4 = 48 So, the three consecutive even numbers that add up to 138 are... 44, 46, & 48