39, 41, 43
Let x represent the smallest of these numbers. From the problem, we know
x+(x+2)+(x+4)=123
Solving for x:
3x+6=123
3x=117
x=117/3=39
So our integers are: 39, 41, 43
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They are: -39 -41 -43 = -123
123/3 = 41 so integers are 39, 41 and 43
There are no three consecutive odd integers who's sum equals 13.
x is lowest of the integers so x + (x + 2) + (x + 4) = 123 ie 3x + 6 = 123 so 3x = 117 and x = 39, so integers are 39, 41 and 43
For three consecutive odd integers to have the sum 123, the equation N + N+2 + N+4 = 123 must be solvable with N being an odd integer.N + N+2 + N+4 = 1233N + 6 = 1233N = 117N = 39Since 39 is an odd integer, the solution is 39, 41, and 43.If N were even, or if N resolved to a non-integer, then the problem would have been incorrectly stated and unsolvable.