Q: What are two factors of 64 that have a sum of 16?

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64 + 16

64

-8x-8=64

64 Factors: 1, 2, 4, 8, 16, 32, and 64.

The factors of 64 are 1, 2, 4, 8, 16, 32, and 64.

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The factors of 64 are 1, 2, 4, 8, 16, 32 and 64. No two of them add up to 19.

64 + 16

64

To tackle this question, you first need to break the number down into its prime factors. In this case we have 64 = 2x2x2x2x2x2 To find the greater factors, you need to multiply any combination of these. That gives us the factors as 2, 4, 8, 16, 32 and 64 Adding these up for the sum gives us 126 Thus the sum of all even factors of 64 is 126.

-8x-8=64

The trivial answers are 0 and 1, 1x1x1x1.... = 1 so it can have 64 factors. Also 2x2x2x2x.... (64 times) = 264 is also a number with 64 factors If you mean 64 prime factors ... 1x2x3x5x7x .... use the first 64 prime numbers.

64 Factors: 1, 2, 4, 8, 16, 32, and 64.

The factors of 64 are 1, 2, 4, 8, 16, 32, and 64.

The common factors of 16 and 64 are 1, 2, 4, 8, and 16.

The common factors of 16 and 64 are 1, 2, 4, 8, and 16

-96

The factors of 64 are 1, 2, 4, 8, 16, 32 and 64