The factors of 64 are 1, 2, 4, 8, 16, 32 and 64. No two of them add up to 19.
It is 126.
83 is the answer. Just add! (:
To tackle this question, you first need to break the number down into its prime factors. In this case we have 64 = 2x2x2x2x2x2 To find the greater factors, you need to multiply any combination of these. That gives us the factors as 2, 4, 8, 16, 32 and 64 Adding these up for the sum gives us 126 Thus the sum of all even factors of 64 is 126.
xy = 64 x + y = 16 y = 16-x x(16-x) = 64 16x -x^2 -64 = 0 x^2 -16x + 64 = 0 (x-8)(x-8) =0 both factors = 8
2^64 =1.8446744e+19
The two numbers that have a product of 64 and a sum of 16 are 8 and 8. Since both numbers are the same, their product is (8 \times 8 = 64) and their sum is (8 + 8 = 16).
64
64 + 16
there is no, because in order for it to have one, one of its factors has to be odd.
36 and 64
64
The numbers are 98 and 64