Q: What two factors of 64 have a sum of 19?

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2^64 =1.8446744e+19

36 and 64

64

The numbers are 98 and 64

Find two numbers if their sum is 64 and their difference is 12. The two numbers are

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It is 126.

83 is the answer. Just add! (:

To tackle this question, you first need to break the number down into its prime factors. In this case we have 64 = 2x2x2x2x2x2 To find the greater factors, you need to multiply any combination of these. That gives us the factors as 2, 4, 8, 16, 32 and 64 Adding these up for the sum gives us 126 Thus the sum of all even factors of 64 is 126.

xy = 64 x + y = 16 y = 16-x x(16-x) = 64 16x -x^2 -64 = 0 x^2 -16x + 64 = 0 (x-8)(x-8) =0 both factors = 8

2^64 =1.8446744e+19

64

there is no, because in order for it to have one, one of its factors has to be odd.

The trivial answers are 0 and 1, 1x1x1x1.... = 1 so it can have 64 factors. Also 2x2x2x2x.... (64 times) = 264 is also a number with 64 factors If you mean 64 prime factors ... 1x2x3x5x7x .... use the first 64 prime numbers.

64 + 16

36 and 64

64

45 and 19 are the numbers.