7 and -7
Wiki User
β 12y ago10
7 and -4
b=a+1 ab=56 a(a+1)=56 a2+a-56=0 (a+8)(a-7)=0 a=7 b=7+1=8
The integers are 5 and 7.
The integers are -7 and -5.
10
+7 and -7.
10
3 and 4
They are -2 and 12.
4 and -7; 4 + -7 = -3 and 4 - (-7) = 4 + 7 = 11
7 and -4
Let the integers be 'n' & 'n+2' Hence Their squares are n^(2) & (n+2)^(2) Their sum is n^(2) + (n+2)^(2) = 74 Expanding n^(2) + n^(2) + 4n + 4 = 74 2n^2 + 4n -70 = 0 n^2 + 2n - 35 = 0 Factor (n - 7)(n + 5) Hence n = '5' & '7' Odd and consecutive.
b=a+1 ab=56 a(a+1)=56 a2+a-56=0 (a+8)(a-7)=0 a=7 b=7+1=8
55
The integers -7 and +7.
The integers are 5 and 7.