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How make triangles does it take to make a hexagon?
With 6 equilateral triangles oriented with a point from each touching in the center of the imagined hexagon, you would have a hexagon. The following would make a 6 pointed star which is not a hexagon because it would have 12 edges: "It takes 2 triangles to make a hexagon. Take one triangle, put a side of it flat down, take a second triangle, and put its point downwards and overlap it with the 1st triangle. Hint; It should make a Star of David. Hope this helped."
Geometric shape with 6 triangles and 1 hexagon?
In 3d a hexagonal pyramid. In 2d, two hexagons. Or a six-pointed star (like a Star of David), a parallelogram plus lots more possibilities
What is the area of one parallelogram in a 8- pointed star?
42
What shape has one hexagon and six triangles?
The first one that comes to mind is the Star of David (Jewish Star).
Is the star of David a star or two triangles?
Yes, it is known as a star, but it is two triangles.It is one upside down triangle on one upward triangle.
What kind of body plan do starfish have?
A star? A hexagon? A Triangle
How make triangles does it take to make a hexagon?
With 6 equilateral triangles oriented with a point from each touching in the center of the imagined hexagon, you would have a hexagon. The following would make a 6 pointed star which is not a hexagon because it would have 12 edges: "It takes 2 triangles to make a hexagon. Take one triangle, put a side of it flat down, take a second triangle, and put its point downwards and overlap it with the 1st triangle. Hint; It should make a Star of David. Hope this helped."
What is a shape that has 6 triangles and 1 hexagon?
In 3d a hexagonal pyramid. In 2d, two hexagons. Or a six-pointed star (like a Star of David), a parallelogram plus lots more possibilities
How many triangles in a star inside a hexagon?
To determine the number of triangles in a star inside a hexagon, we need to consider the number of triangles formed by the lines connecting the vertices of the hexagon and the points where the lines of the star intersect. Each intersection point forms a triangle with two adjacent vertices of the hexagon. Therefore, if the star has n points of intersection, the total number of triangles would be n multiplied by 2. Additionally, we need to consider the triangles formed by the lines of the star itself, which would add n triangles to the total count. So, the total number of triangles in a star inside a hexagon would be 3n.
Geometric shape with 6 triangles and 1 hexagon?
In 3d a hexagonal pyramid. In 2d, two hexagons. Or a six-pointed star (like a Star of David), a parallelogram plus lots more possibilities
What is a shape that has 6 sides and looks like a star and a hexagon in the middle?
Anything with 6 sides is a hexagon.
What is the names of all 2d shapes?
line, square, circle, triangle, quadrilateral, pentagon, hexagon, heptagon, octagon, nonagon, decagon, polygon, star, rhombus, trapezoid, parallelogram * * * * * A line is one-dimensional. And what about ellipses, ovals, a square with one side replaced by a curve, irregular shapes?
What is the area of one parallelogram in a 8- pointed star?
42
What shape has one hexagon and six triangles?
The first one that comes to mind is the Star of David (Jewish Star).
Is the star of David a star or two triangles?
Yes, it is known as a star, but it is two triangles.It is one upside down triangle on one upward triangle.
How do you find the perimeter of of a parallelogram?
If the parallelogram is sideways like the small sides are crooked and the bottom lines are straight then you have to add all the sides to get your answer.Measure any two adjacent sides. Sum them, then multiply by two.It's the sum of the lengths of all sides that form a parallelogram.Perimeter is the distance around an object. If we have a parallelogram with a length 12 and width 5, then 5+5+12+12 which is equal to 34. Same with trapezoid, rectangle, triangle, star, etc.P = 2l + 2w
Are the star of David and the witches hexagon the same?
Whether or not hey are the same, they are not hexagons.
