the ratios in such a triangle are 1:2:sqrt(3)
so the longest length is opposite the 90 degree angle and is twice as large as the length opposite the 30 degree angle
Divide the length of a side of one triangle by the length of the corresponding side of the other triangle.
5to3
The length of the longer leg equals the length of the shorter leg times the square root of three.
In such a triangle, the sides will always be in the ratio, 1, 2 (hypotenuse) and sqrt(3) So the ratio you want is sqrt(3)/2
Assuming that 30-60-90 refers to the angles (in degrees), the ratio of the longer leg to the hypotenuse would be 1:cosine(30) = 1:sqrt(3)/2 or 2:sqrt(3)
In a 30° 60° 90° triangle, the ratio (long leg)/hypotenuse = sqrt(3)/2 ~ 0.866The ratio (short leg)/hypotenuse = 1/2 = 0.5
2 Square Root 3 And 4
1/2 sqrt(3) = 0.866 (rounded)
1/2 sqrt(3) = 0.866 (rounded)
Starting with an equilateral triangle of side 2, dropping a perpendicular from one vertex to the opposite base creates two equal right angled triangles with hypotenuse of length 2, base length 1 and height of length √(22 - 12) = √3 which is the longer leg of the 30-60-90 triangle. Thus the ratio of longer_leg : hypotenuse is √3 : 2
Divide the length of a side of one triangle by the length of the corresponding side of the other triangle.
5to3
The length of the longer leg equals the length of the shorter leg times the square root of three.
In such a triangle, the sides will always be in the ratio, 1, 2 (hypotenuse) and sqrt(3) So the ratio you want is sqrt(3)/2
Assuming that 30-60-90 refers to the angles (in degrees), the ratio of the longer leg to the hypotenuse would be 1:cosine(30) = 1:sqrt(3)/2 or 2:sqrt(3)
It depends on whether the ratio refers to the angles of the triangle or the length of the sides.
The ratio of the length of the side of a right angle triangle must be 3,4,5 16,56,65 are not in that ratio.