Lxi h,xx50 mov a,m inx h mov b,m mvi ,ffh inr c sub b jnc xx08 add b inx h mov m,c inx h mov m,a hlt
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M and N
you use mx+b m is slope. m always has to be next to x b is y intercept
finding the equation of a line of (-1,2) and (1,2): formula: y=mx+b m = slope b = y intercept first find m: m=(y2-y1)/(x2-x1) so, m=(2-2)/ (1- -1) m=0 since you now know m you can plug that in to the formula: y=0x+b to get b: plug in the coordinates (either (-1,2) or (1,2)), it comes out the same (-1,2). y=mx+b or 2=0 × -1+b, ==>solving for b: b=2-(0)(-1). b=2 (1,2). y=mx+b or 2=0 × 1+b, ==>solving for b: b=2-(0)(1). b=2 you now know that m=0 and b=2, now plug that back in the equation to get: y=mx+b y=0x+2 y+2 It's confusing, but it works!
the next letter would be 'b'
It's CDL
m
H. H. B. M. Thomas has written: 'The calculation of the rotary lateral stability derivatives of a jet-flapped wing'
Lxi h,xx50 mov a,m inx h mov b,m mvi ,ffh inr c sub b jnc xx08 add b inx h mov m,c inx h mov m,a hlt
In order to add 32 bit numbers in the 8085, you need to add them 8 bits at a time, tracking the carrys between each add. LXI B,first_number LXI H,second_number LXI D,result LDAX B ;first byte - no carry in ADD M STAX D INX B; point to next byte INX D INX H LDAX B ;second byte - carry in ADC M ;note the ADC instead of ADD STAX D INX B; point to next byte INX D INX H LDAX B ;third byte - carry in ADC M STAX D INX B; point to next byte INX D INX H LDAX B ;fourth - carry in ADC M STAX D
3 blind mice
e öX` ñneu ào_ H$Wm e Hw$R>o hmoVmg Vy, Vwbm A¸$b Amho H$m,Jobo XmoZ Vmg _r gmaIr Vwbm H$m°b H$aVo`, ~K VwÂ`m _mo~mB©b da -{_g-H$m°b AgVrb.Vwbm H$er ao OamgwÕm _mPr H$miOr Zmhr. H$m` g_OVmog Vy H$moU ñdVmbm? AJ hmo hmo hmo, {H$Vr AmoaS>erb _r Var H$m
A=m*h m=(a+b)/2
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M. B. Subrahmanyam has written: 'Finite horizon H [infinity] and related control problems' -- subject(s): H
"F". The sequence follows the alphabet in reverse order, skipping three letters each time: a (skip z) z (skip y) e (skip o) b (skip n) I (skip h) y (skip v) o (skip m), then the next letter is "f".