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How do you solve n3 plus 2n2 - 15n equals 0 by factoring?
n3 + 2n2 - 15n = 0 : extract n as a factor of all the left hand terms then, n(n2 + 2n - 15) = 0 : the expression n2 + 2n - 15 can be factored as (n + 5)(n - 3) then, n(n + 5)(n - 3) = 0 : This holds true when either n = 0, or n + 5 = 0 or n - 3 = 0 When n + 5 = 0 then n = -5 : When n - 3 = 0 then n = 3. The solutions are n = 0 or n = -5 or n = 3.
Which expression models the phrase 15 greater than a number n plus 15 15 plus n n-15 plus n?
n plus 15.n plus 15.n plus 15.n plus 15.
Why 0 has only one multiple?
Because 0 is nothing. Therefore, you can add infinity 0s=0 Also, 0*N=0, N-0=0, and 0+N=N, but you can't do N/0, because 0 is nothing. ( N= any number)
What is the sum of the whole numbers from 5 up to 100?
its 5035the summarian notation tells you that(sum of all #from 0 to a number'N'(sum of all #from 0 to N) = (n)+(n-1)+(n-2)+(n-3)+...+(2) +(1) or(sum of all #from 0 to N) = (1)+ (2) + (3) + (4)+...+(n-1)+(n)the two different sums are aligned by columns. now add the two colunms accordingly and you'll get2x(sum of all #from 0 to N)=(n+1)+(n+1)+...+(n+1) (n+1)is added n timesso2x(sum of all #from 0 to N) =n(n+1)(sum of all #from 0 to N) =n(n+1)/2so (sum of 5 to 100) = (sum of 0 to 100)- (sum of 0 to 5)=100(101)/2 - 5(6)/2 = 5050 - 15 = 5035
What is the next number in series 4 8 15 25 38?
To determine the pattern in the series 4, 8, 15, 25, 38, we can calculate the differences between each consecutive number: 8-4=4, 15-8=7, 25-15=10, and 38-25=13. We can observe that the differences are increasing by consecutive odd numbers (3, 5, 7, 9...). Therefore, the next number in the series would be 38 + 15 = 53.
