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There is no symbol before 4a so the question contains two expressions.
6-3a**2+7+4a-5a+18 3a**2-1a+31
Not sure why it is 3a2- if you mean 3*a*2, then: 3*a*2=6a (6a-2a)+5-2(a (or a2)+a)=1 4a+5-(2a+a)=1 4a+5-2a-a=1 Then take the 5 over (remember, the +5 become -5 when transposed): 4a-2a-a=1-5 Solving the equations on both sides gives: a=-4 Is this your answer?
If you take the common term 4a out of the expression 16a4 + 4a3, you get 4a(4a3 + a2), making it apparent that if you divide by 4a, the quotient is (4a3 + a2).
is that ment to be a > sign? well if it is3a>4a-5 (-4a)-a>-5 then just inverta>5
12a
(a + 2)(3a - 2)
3a2
6-3a**2+7+4a-5a+18 3a**2-1a+31
Yes 4a+16 is an expression with 2 terms
The expression is: (4a+b)/(2a-5b)
A variable expression is an expression which contains variables(symbol that represents a certain value). For example, 4a-90. 4a-90 would be the expression an a is a variable
Not sure why it is 3a2- if you mean 3*a*2, then: 3*a*2=6a (6a-2a)+5-2(a (or a2)+a)=1 4a+5-(2a+a)=1 4a+5-2a-a=1 Then take the 5 over (remember, the +5 become -5 when transposed): 4a-2a-a=1-5 Solving the equations on both sides gives: a=-4 Is this your answer?
It is an expression of two terms as: 4a+12
7a-17 = 4a+1 7a-4a = 1+17 3a = 18 a = 6
Expression ... Anything without an = sign is an expression
10
14a - 4a + 5a - 3a = 12a