2a3 - 128 = 2*(a3 - 64) = 2*(a -4)*(a2 + 4a + 16)
(a - b + 2)(a + b + 2)
The equation cannot be solved as there are two unknowns. However it can be simplified and the two unknowns (a and b) expressed in terms of the second unknown. 1) Expressing a in terms of b 4a + 2 = 3b - 5 4a = 3b -7 if desired this could be stated as a = (3b - 7)/4 2) Expressing b in terms of a 3b - 5 = 4a + 2 3b = 4a + 7 if desired this could be stated as b = (4a + 7)/3
there are 2
(4a)2 or 16a2
2a3 - 128 = 2*(a3 - 64) = 2*(a -4)*(a2 + 4a + 16)
a-16 = a/4+2 Multiply all terms by 4: 4a-64 = a+8 4a-a = 8+64 3a = 72 a = 24
It is an expression that can be simplified to: 4a+2
(a - b + 2)(a + b + 2)
a = -2-4a/3-2 = 8-4a = 8(3-2) times both sides by (3-2)-4a = 24-16-4a = 8-a = 2 divide both sides by 4a = -2 times both sides by -1
4a + 7
The equation cannot be solved as there are two unknowns. However it can be simplified and the two unknowns (a and b) expressed in terms of the second unknown. 1) Expressing a in terms of b 4a + 2 = 3b - 5 4a = 3b -7 if desired this could be stated as a = (3b - 7)/4 2) Expressing b in terms of a 3b - 5 = 4a + 2 3b = 4a + 7 if desired this could be stated as b = (4a + 7)/3
−4a + 139 = 4a + 123 → −8a = −16 → a = 24a + 123 → 4(2) + 123 = 8 + 123 = 131°
8
(a + 4)(a^2 - 4a + 16)
An expression consisting of 2 terms. 6A + 6B.
It is an expression of algebraic terms with no equality sign