Well, honey, let me break it down for you. 69360 is divisible by 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 16, 18, 20, 24, 30, 32, 36, 40, 45, 48, 60, 64, 72, 80, 90, 96, 120, 144, 160, 180, 240, 288, 320, 360, 480, 576, 720, 960, 1440, 2880, and of course, itself, 69360. So, it's safe to say this number is quite the popular one at the divisibility party.
The number 36940 is divisible by 12 because it meets the criteria for divisibility by both 3 and 4. To check for divisibility by 3, we sum the digits (3 + 6 + 9 + 4 + 0 = 22), and since 22 is not divisible by 3, we need to reassess. However, for divisibility by 4, the last two digits (40) are divisible by 4. Since it fails the divisibility test for 3, 36940 is not divisible by 12.
A number is divisible by 6 if the number is divisible by 2 AND 3.
To determine if a number is divisible by 4, check if the last two digits form a number that is divisible by 4. For divisibility by 8, the last three digits of the number must be divisible by 8. Essentially, a number that meets the criteria for both divisibility by 4 and 8 will have its last two digits divisible by 4 and its last three digits divisible by 8.
Any even number is divisible by 2.
678 is divisible by 3.
It is divisibility by 3 and divisibility by 5.Divisibility by 3: the digital root of an integer is obtained by adding together all the digits in the integer, with the process repeated if required. If the final result is 3, 6 or 9, then the integer is divisible by 3.Divisibility by 5: the integer ends in 0 or 5.
If a number is divisible by 3 and 5, it is divisible by 15.
A number is divisible by 6 if the number is divisible by 2 AND 3.
a number is divisible by 9 if the sum of the digits is divisible by 9.
10 is divisible by 1,2,5, and 10.
Divisibility refers to integers, not decimals.
The divisibility rules for a prime number is if it is ONLY divisible by 1, and itself.
Any even number is divisible by 2.
4 is divisible by 1, 2 and 4.
If a number is divisible by 3, and also by 4, then it is divisible by 12 - so you might use the divisibility rules for those two numbers. Although it might be simpler just to perform the division.
the # needs to be divisible by 2 and 3.
Yes.