Both 7 and 13 are factors of their least common multiple, which is 91. Additionally, they both divide evenly into any multiple of 91, such as 182 or 273. Therefore, any multiple of 91 can be expressed as a product involving both 7 and 13.
91 = 13 x 7 Can't go any further as both 13 and 7 are prime numbers.
9 and 13 both go into 117.
x - 7 - 4 = 13 (-7 - 4 = -13) x - 11 = 13 add 11 to both sides x = 24
the answer -7+x=13 add 7 to both sides. cancel the first set of sevens leavening you with the x and add 13+7=20
7/13 is already in its most sim plified form. Reason ; both '7' and '13' are prime numbers , and therefore do not have any common factors.
91 = 13 x 7 Can't go any further as both 13 and 7 are prime numbers.
9 and 13 both go into 117.
91 divided by 13 = 7 13 can go into 91 7 times
16 and 13 both go into any multiple of 208 .
-8x -7 = 3x - 13 Add 8x to both sides: -7 = 11x - 13 Add 13 to both sides: 6 = 11x Divide both sides by 11: x = 6/11
The prime factorization of 91 is 13 x 7 They are both prime so its a prime factorization
x - 7 - 4 = 13 (-7 - 4 = -13) x - 11 = 13 add 11 to both sides x = 24
Both are prime numbers and a prime number is only divisible by 1 and itself.
the answer -7+x=13 add 7 to both sides. cancel the first set of sevens leavening you with the x and add 13+7=20
Well, honey, 13 and 9 both go into numbers that are multiples of both 13 and 9. So, the numbers that both 13 and 9 go into are the common multiples of 13 and 9, like 117. Hope that clears things up for you, darling.
7/13 is already in its most sim plified form. Reason ; both '7' and '13' are prime numbers , and therefore do not have any common factors.
1, 7, 13, 91 (1 x 91, 7 x 13).