Every multiple of 48 is a multiple of both 16 and 12. There are an infinite number of them. multiples of 16, 16,32,48,64,etc. multiples of 12, 12,24,36,48,60,etc. common multiples of both 12 and 16 are the multiples of 48, 48,96,144,etc
12
Suppose 12 is the GM of 16 and x then 12 = sqrt(16*x) squaring both sides: 144 = 16*x so that x = 9
8, 4, 12, 16, etc.
13 is the only prime number between 12 and 16.
16 - x > 12 First add x to both sides: 16 > 12 + x Now subtract 12 from both sides: 4 > x x < 4
Every multiple of 48 is a multiple of both 16 and 12. There are an infinite number of them. multiples of 16, 16,32,48,64,etc. multiples of 12, 12,24,36,48,60,etc. common multiples of both 12 and 16 are the multiples of 48, 48,96,144,etc
12
The smallest whole number divisible by both 8 and 12 is 24.
Suppose 12 is the GM of 16 and x then 12 = sqrt(16*x) squaring both sides: 144 = 16*x so that x = 9
8, 4, 12, 16, etc.
32
The ratio number of 16 girls to 12 boys is either 16:12 or 16 to 12.
13/16 3+9=12 4+8=12 12 is divisible by 3 39/3=13 48/3=16 13/16 can not both be divided by the same number (13 is a prime number)
It either means: 16x+12 or 16(x+12) the two are certainly not interchangeable. I listed both because of the ambiguity of your question.
Let's label one of the numbers with x, and the other number with y. So, x + y = 25 4x - 12 = 2y + 16 add 12 and subtract 2y to both sides of the second equation; x + y = 25 4x - 2y = 16 +12 multiply by -4 the first equation; -4x - 4y = -100 4x - 2y = 16 +12 add both equations in order to eleminate x; 0 - 6y = -72 multiply by -1 to both sides; 6y = 72 divide by 6 both sides; y = 12 Substitute 12 for y into the first equation; x + y = 25 x + 12 = 25 subtract 12 to both sides; x = 13 Thus, the numbers are 13 and 12. Check: 13 + 12 = 25 4(13) -12 = 2(12) +16 ? 52 -12 = 24 + 16 ? 40 = 40
Both 16 and 12 can be divide by for, which results in 4/3. You can change for thirds into a mixed number. 4 divided by 3 is 1 remainder 1, so as a mixed number, 4/3 is 11/3.