One means by which a nozzle can be forced to operate at maximum thrust or "on design" under many different flight conditions is through a.variable geometry. For such a nozzle, the area of the exit, throat, or both is varied so that the optimum exit pressure can be obtained. Two nozzle shapes are usually used: a simple circular (iris) nozzle or a plug nozzle. Note that variable nozzles are typically not used on commercial aircraft because of the limited flight envelope -that is, the craft and engine basically are optimally designed for one altitude and flight condition. Military fighters, on the other hand, must be designed to operate under a variety of conditions, including aircraft carrier takeoff. As a result, most of these engines have variable nozzles.
There are two possible ways: The first is to obtain a formula for the area which depends on a variable (the base). For example, consider all triangles with a base of x cm and a height of 4 cm. What is their area? Answer: it is 1/2*height*base = 1/2*4*x = 2x cm2. So I have an answer which includes the variable representing the base. The second possibility is that there is supplementary information that allows you (if you work hard enough) to find a value for the base.
1. Elimination: Select two equations and a variable to eliminate. Multiply each equation by the coefficient if that variable in the other equation. If the signs of the coefficient for that variable in the resulting equations are the same then subtract one new equation from the other. If they have opposite signs then add them. You will now have an equation without that variable. Repeat will other pairs and you will end up with one fewer equation and one fewer variable. Repeat this process: after each round you will have one fewer equation and one fewer variable. Keep going until you are left with one equation in one variable. Solve that. Then work backwards solving for the other variables.2. Substitution: Select a equation and a variable. Make that variable the subject of the equation. The right hand side of this equation is an expression for that variable. Substitute this expression for the variable is each of the other equations. Again, one fewer equation in one fewer variable. Continue until you are left with one equation in one variable. Solve that. Then work backwards solving for the other variables.3. Matrix inversion: If A is the nxn matrix of coefficients, X is the nx1 [column] matrix of variables and B is the nx1 matrix of the equation constants, then X = A^-1*B where A^-1 is the inverse of matrix A.
An independent variable is basically a variable that can be any number. The dependent variable is the variable calculated from the independent variable. For example, I do contract work where I get paid for every hour of work I do in a given week. If I work more hours, my paycheck is bigger. So in this case the number of hours I work is the independent variable (it can, in theory, be anywhere from 0 to 40 or more hours each week), and the dependent variable is the amount on my paycheck (it is a variable too, but it directly depends on the number of hours I worked).
A discrete variable is a variable that has a certain set limit. For example, a ten point scale can ONLY have the variables 1, 2, 3, 4, 5, 6, 7, 8, 9, & 10. 2.8 would not work on a discrete variable ten point scale. Height is an example of a continuous variable, or one that has an infinite possibility.
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when trigger pulled it sucks water from the storage area and dispenses it out the nozzle
A work area is a type of slot in memory for opening tables. These slots are numbered, but once a table is opened, they can also be referred by the name of the table opened (more precisely: by its alias). Here is an example of opening tables: * close all tables first, just in case close database all * open table "client" in work area 1 select 1 use client * open table "invoice" in work area 2 select 2 use invoice * go back to table client, and set an index order select client && "select 1" would also work here set order to ClientId Instead of "select 1" and "select 2", in the above examples, it is preferable to issue "select 0", letting FoxPro automatically select an available work area.
The Wedco Nozzle is a CARB compliant spill-proof gas can nozzle. With the nozzle in place you can invert your gas can and it will not leak. Then simply push the nozzle lock and push the nozzle against the rim of the filling throat of the tank you're filling to start the flow of fuel. If you lift the nozzle away from the rim the flow stops.
I have had several experiences that the nozzles of my Black Flag pesticide cans do not work. I pushed it down but the gas just did not come out. Is the nozzle jammed inside the can? Somehow the pressurization mechanism does not work?
No, you have to buy the nozzle that will much the pocket hose, you can find it online at eBay, Amazon etc...
The impeller spins and compresses water into the jet nozzle. This creates a high pressure area. This water is shot out the back, and the steering nozzle diverts left and right to steer the ski. Engine cooling water is bled off the high pressure area (90 degree brass elbow) and routed though the engine, exhaust, water box and out the hull..
You don't. I had this problem on my 2002 Envoy and there was no way to clear the blockage. I tried putting the nozzle in warm soapy water and shaking it to remove the blockage, but that didn't work. I tried soaking it in alcohol and shaking it to remove the bllockage, but that didn't work. Finally I took a paper clip and worked it around inside the nozzle. No luck. Everything I did made it worse. You have to replace the nozzle.
costants what controlls it as in what causes your projeect to failed what variable cause it to do good.what variable made a mess what variable cause it to work
I have variable hours of work; today I will leave early.
An air horn is simply a canister of compressed air, which at the press of a button realeses some of the air into a nozzle. When air passes through the nozzle, a sound is emitted. (like a trumpet)
motivation to work is a moderating varaible , because it is not aleways consisitent adn there are various factors which go about in making a person work
Select one equation from a system of linear equations. Select a second equation. Cross-multiply the equations by the coefficient of one of the variables and subtract one equation from the other. The resulting equation will have one fewer variable. Select another "second" equation and repeat the process for the same variable until you have gone through all the remaining equations. At the end of the process you will have one fewer equation in one fewer variable. That variable will have been eliminated from the system of equations. Repeat the whole process again with another variable, and then another until you are left with one equation in one variable. That, then, is the value of that variable. Substitute this value in one of the equations from the previous stage to find the value of a last variable to be eliminated. Work backwards to the first variable. Done! Unless: when you are down to one equation it is in more than one variable. In this case your system of equations does not have a unique solution. If there are n variables in your last equation then n-1 are free to take any value. These do not have to be from those in the last equation. or when you are down to one variable you have more than one equation. If the equations are equivalent (eg 2x = 5 and -4x = -10), you are OK. Otherwise your system of equations has no solution.