x+1+7x-3 Simplify adding the x terms and the numbers separately So it becomes x+7x+1-3 = 8x-2
7x+8-x-7 6x+1
x=(-9/7) 7x+12=3 7x=(-9) x=(-9/7)
7x = 4x+2x+1xSo 7x/2 = 4x/2 + 2x/2 + x/2 (by the distributive property of division over addition) = 2x + x + x/2
3x/4 + x = 7x/4 because 4x/4 = x 3x/4 + 4x/4 = 7x/4
x+1+7x-3 Simplify adding the x terms and the numbers separately So it becomes x+7x+1-3 = 8x-2
7x+8-x-7 6x+1
x=(-9/7) 7x+12=3 7x=(-9) x=(-9/7)
(x + 3)(x + 4) = x2 + 7x + 12
7x = 4x+2x+1xSo 7x/2 = 4x/2 + 2x/2 + x/2 (by the distributive property of division over addition) = 2x + x + x/2
3x/4 + x = 7x/4 because 4x/4 = x 3x/4 + 4x/4 = 7x/4
Nice trinomial. Thanks for sharing. It's equal to (x + 5) (x + 2) .
X=4.2666666666667
Assuming that what you're looking for is the values of x: x2 + 7x = 8 x2 + 7x - 8 = 0 (x + 8)(x - 1) = 0 x is equal to either -8 or 1.
The problem can be written as:46-3+7x-15 = 4243+7x-15=427x + (43-15) = 427x + 28 = 427x = 42 - 287x = 14x = 14/7 = 2
Your question is not quite clear but: x2+7x-70 = (x+17)(x-10) when factored
In 7x+7, x is a variable.