x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
(x + 5)(x + 2)
(x + 10)(x - 3)
x2+7x-8 = (x-1(x+8)
(x-5)(x-2)
The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth
1
x2+7x+12
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
x2 + 7x + 6 = (x + 6) (x + 1)
x^2+7x-30 = (x-3)(x+10)
(x + 5)(x + 2)
(x - 5)(x - 2)
(x + 10)(x - 3)
x2 + 7x - 8 = (x + 8)(x - 1)
x2+7x-8 = (x-1(x+8)