17/11x3=4.63636363636363636363636363636363636363(repeats forever)
The answer is 3 because 33 is 11x3 and 27 is 3x3x3 so the answer is 3
6x3=18 11x3=33 so 6=18 11=33
9E-05x
30. t(n) = (11x3 - 78x2 + 169x - 90)/6 for n = 1, 2, 3, ...
11x3
36.
no 11x3=33
33+0, 11x3
17/11x3=4.63636363636363636363636363636363636363(repeats forever)
1 x 33, 3 x 11 = 33
The answer is 3 because 33 is 11x3 and 27 is 3x3x3 so the answer is 3
Find all rational roots of: x5 - 2x4 + 11x3 - 22x2 - 12x + 24 = 0
using mod 12 arithmetic, 11x3 = 9 mod 12
6x3=18 11x3=33 so 6=18 11=33
9E-05x
It is x4 + 11x3 + 41x2 + 61x + 30.