12 eggs is a dozen
12 dozens in a carton?
mean in math mean the average Ex. 12 + 12 =24 now divide that by 2 the answer is 12
5 numbers: A, B, C, D, E.median is 2: A, B, 2, D, E. Since median is 2, then A or B can be 0 or 1. So we can have:0, 0, 2, D, E0, 1, 2, D, E1, 0, 2, D, E1, 1, 2, D, E So that D ≥ 3 or D ≤ ?MEAN: (A + B + 2 + D + E)/5 = 10A + B + 2 + D + E = 50A + B + D + E = 48So, you need to study all the possibilities for A, B, and D, in order to find E. For example,If A = 0, B = 0, and D = 3, then E = 45.If A = 1, B = 1,and D = 4, then E = 40....
if a + b = e. e + d = e + d. that's the answer: e + d or it could be e + d = (a + b) + d but in simplest form, its e + d
For a hint, they are usually scrambled, boiled, or fried and served with breakfast. The E is the first letter of what they are, and the 12 and the D are different ways of saying how many there are.
Assuming by "numbers" you mean "whole numbers":{10, 10, 12, 13, 15}If the five numbers are {a, b, c, d, e} with a ≤ b ≤ c ≤ d ≤ e, then:median = 12 → c = 12leaving only two numbers (a, b) ≤ 12.mode = 10 → two or more numbers equal 10 (which is less than 12) → a = b = 10The final two numbers (d, e) are not equal, both greater than 12, and such that the sum of all five numbers is 60.10 + 10 + 12 + d + e = 60 → d + e = 28 → d = 13, e = 15→ {a, b, c, d, e} = {10, 10, 12, 13, 15}[If "numbers" includes "decimal numbers" (ie numbers with a fractional part), then as long as d + e = 28 and 12 < d < e there are infinitely many solutions, eg {10, 10, 12, 12.5, 15.5}, {10, 10, 12, 13.75, 14.25}]
The sum of four numbers equals 40: a+b+c+d=40 Those same four numbers, along with another number (e), give the set a mean of 12: (a+b+c+d+e)/5=12 Use these two facts to determine e as follows: (a+b+c+d+e)/5=12 a+b+c+d+e=60 (a+b+c+d)+e=60 40+e=60 e=20
12 eggs in a dozen
12 eggs in a dozen
12 eggs is a dozen
12 dozens in a carton?
E. D. Smith was born on 1853-12-08.
12=eggs in a dozen
12 eggs in a dozen.
12 eggs in a dozen
jupiter had 12 days