Assuming that the problem looks like this: (12/jk)(3k/4)
Multiplying fractions is much easier than adding them. When adding, we need to make sure they both have a common denominator. But With multiplication, we can just multiply the numerator by the numerator and the denominator by the denominator.
So we get (12/jk)(3k/4)=(36k)/(4jk)
Now we just need to simplify. We can divide by 4 and cancel a k, giving us 9/j.
-47 + 6k = 3k - 2Add 47 to each side:6k = 3k +45Subtract 3k from each side:3k = 45Divide each side by 3:k = 15
3k+16 = 5k subtract 3k from both sides 16 = 2k divide both sides by 2 8 = k
Yes, it is true.
k2 + 3k =108k2 + 3k - 108 = 0(k - 9) (k + 12)k = -9 , k = 12ANSWER:k = -9 , k = 12I hope this helps!
(j^3 + 3k^4)(j^6 - 3j^3k^4 + 9k^8)
( 12/jk ) x ( 3k/4 ) = 9/j
D = 3K; D + 12 + K + 12 = 10K so 3K + 12 + K + 12 = 10K so 24 = 6K Kumar is 4 and Dollah is 12. In 12 years they will be 16 and 24, total 40 which is 10 times Kumar's present age. Job done.
it is a number
-47 + 6k = 3k - 2Add 47 to each side:6k = 3k +45Subtract 3k from each side:3k = 45Divide each side by 3:k = 15
3k+16 = 5k subtract 3k from both sides 16 = 2k divide both sides by 2 8 = k
16 - 3k + 5 and k is 4, then 16 -12 + 5 = 9
By using algebra.
Yes, it is true.
K/3 + k/4 = 1 LCD=12 *divide lcd by denominator* K(4) + K(3) = 12(1) 4k + 3k = 12 7k = 12 k=12/7
k2 + 3k =108k2 + 3k - 108 = 0(k - 9) (k + 12)k = -9 , k = 12ANSWER:k = -9 , k = 12I hope this helps!
(j^3 + 3k^4)(j^6 - 3j^3k^4 + 9k^8)
3k..