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9 minus 2k-3 equals k show work and solve?
9 - 2k - 3 = k Add 2k to both sides: 9 - 3 = k + 2k Combine like terms: 6 = 3k Divide both sides by 3: 2 = k
3K-1 equals K plus 2?
3k-1=k+2 2k=3 k=3/2=1.5
What is 2k plus k?
3,000 Get it. It is a math joke. K is often meant as a thousand.
How you would determine what fraction strips all same denominator would fit exactly under 1 2 1 3 what are they?
They are 3k/6k and 2k/6k where k is any non-zero integer.
What is 12 5x -3 solve for x?
x = 3
9 minus 2k-3 equals k show work and solve?
9 - 2k - 3 = k Add 2k to both sides: 9 - 3 = k + 2k Combine like terms: 6 = 3k Divide both sides by 3: 2 = k
What is the factor of 6k2-k-12?
6k2 - k - 12 (2k - 3)(3k + 4) k = 3/2 and -4/3 1.5 and -1.33 are the factors
What is 3k times 2k?
3k times 2k is calculated by multiplying the coefficients and the variables separately. The coefficients 3 and 2 multiply to give 6, while k times k equals k squared (k²). Therefore, 3k times 2k equals 6k².
How do you solve 3k plus 3 equals 8?
3k + 3 = 8 3k = 8 -3 3k = 5 k = 5/3
3K-1 equals K plus 2?
3k-1=k+2 2k=3 k=3/2=1.5
Solve for k 2k-3 equals 11?
ASSs a. c. 8 b. 7 d. 12
How do you find the product for this problem 3kminus6 times2k plus 1?
The question is unclear, so the author will provide answers for a number of interpretations: 1. 3k-6(2k+1) = 3k-12k-6=-9k-6=-3(3k+2) 2. 3k-6(2k)+1=3k-12k+1=-9k+1 3. (3k-6)(2k)+1 = 6k^2 -12k + 1 = 6(k-1-sqrt(5/6))(k-1+sqrt(5/6)) 4. (3k-6)(2k+1) = 6k^2 - 12k + 3k - 6 = 6k^2 -9k + 6 = 3(2k^2 - 3k + 2) Line 4 cannot be factorised further. sqrt and ^2 refer to the square root, and squared respectively. Lines 1 and 2 require knowledge of expansion of linear equations, addition of like terms, and factorisation of linear equations. Lines 3 and 4 also require knowledge of addition of like terms, and expansion and factorisation of quadratic equations. In no case can an exact value for k be determined as we were given an expression rather than an equality.
What is the answer to (7k-3)(k2-2k 7)?
To simplify the expression ((7k - 3)(k^2 - 2k + 7)), you need to apply the distributive property (also known as the FOIL method for binomials). Multiplying each term in (7k - 3) by each term in (k^2 - 2k + 7) gives: [ 7k \cdot k^2 - 14k + 49 - 3k^2 + 6k - 21 ] Combining like terms results in: [ (7k^3 - 3k^2 - 8k + 28). ] Thus, the final simplified expression is (7k^3 - 3k^2 - 8k + 28).
How do you solve 6k 7 3k minus 8 algebra?
To solve the equation (6k + 7 - 3k - 8 = 0), first, combine like terms. This gives you ( (6k - 3k) + (7 - 8) = 0), which simplifies to (3k - 1 = 0). Next, isolate (k) by adding 1 to both sides, resulting in (3k = 1), and then divide by 3, yielding (k = \frac{1}{3}).
How do you solve the equation 43-3k equals -5?
1). Add ' 3k ' to each side of the equation. 2). Add ' 5 ' to each side. 3). Divide each side by ' 3 ' .
How do you find the straight line equation given only that the slope is k passing through a point 3 and 2k on the line?
Suppose P = (x, y) are the coordinates of any point on the line. Then the segment of the line joining P to the point (3, 2k) has slope k That is, (y - 2k) / (x - 3) = k Simplifying, y - 2k = kx - 3k or y = kx - k equivalently, y = k(x - 1)
What is the equation of 2k equals 5k-30?
2k = 5k-30 Subtract 5k from both sides: -3k = -30 Divide both sides by -3 to find the value of k remembering that a minus divided into a minus becomes a plus: k = 10
