n/27=2n/27*27=2*27n=54
n + 18 = 27 subtract 18 to 18 and 27 18-27=9 n = 9
1: (n-2)2 2: n-22 3: n+2n-2 4: n-2n+2 If I understand your question correctly (it is really confusing) then none of the expressions 2 3 or 4 equal the first expression.
Suppose the number is n, then n/7 - 1 >= 2 Add 1 to both sides: n/7 >= 3 Multiply both sides by 7: n >= 21
Numbers. i^n = i^(n mod 4). With n = 27, 27 mod 4...
The two equal numbers that have a sum of 54 are 27 and 27. When you add these two numbers together, you get 54. This is because the sum of two equal numbers will always be double the value of one of the numbers. In this case, 27 + 27 = 54.
Difficult to tell without brackets, but (n-1)*(n+1) = n^2 - 1 [in other words, n squared minus 1] is a useful algebraic identity.
n/27=2n/27*27=2*27n=54
n + 18 = 27 subtract 18 to 18 and 27 18-27=9 n = 9
Oh honey, that's just n times n minus n. So, n squared minus n is just n times (n-1). Hope that clears things up for ya, darling.
1: (n-2)2 2: n-22 3: n+2n-2 4: n-2n+2 If I understand your question correctly (it is really confusing) then none of the expressions 2 3 or 4 equal the first expression.
write N..I..N..E with the picks
Suppose the number is n, then n/7 - 1 >= 2 Add 1 to both sides: n/7 >= 3 Multiply both sides by 7: n >= 21
Numbers. i^n = i^(n mod 4). With n = 27, 27 mod 4...
n=10/7. i did this one mentally. but are you sure its 8n minus negative 4n or is it 8n minus 4n? 8n- -4n does not equal 8n-4n 8n- -4n is the same as 8n+4n
x to the n divided by x to the n is 1. By the law of powers x to the power n divided by x to the power n is x to the power (n minus n), ie x to the power zero. Things which are equal to the same thing are equal to each other. Therefore x to the power zero = 1. (Unless x = zero!)
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals". There is no symbol between the first n and 1. Assuming the question is about (n-1)*(n+1) , this is identically equal to n2-1