n/27=2n/27*27=2*27n=54
n + 18 = 27 subtract 18 to 18 and 27 18-27=9 n = 9
1: (n-2)2 2: n-22 3: n+2n-2 4: n-2n+2 If I understand your question correctly (it is really confusing) then none of the expressions 2 3 or 4 equal the first expression.
Suppose the number is n, then n/7 - 1 >= 2 Add 1 to both sides: n/7 >= 3 Multiply both sides by 7: n >= 21
Numbers. i^n = i^(n mod 4). With n = 27, 27 mod 4...
The two equal numbers that have the sum of 54 are 27 and 27.
Difficult to tell without brackets, but (n-1)*(n+1) = n^2 - 1 [in other words, n squared minus 1] is a useful algebraic identity.
n/27=2n/27*27=2*27n=54
n + 18 = 27 subtract 18 to 18 and 27 18-27=9 n = 9
Oh honey, that's just n times n minus n. So, n squared minus n is just n times (n-1). Hope that clears things up for ya, darling.
1: (n-2)2 2: n-22 3: n+2n-2 4: n-2n+2 If I understand your question correctly (it is really confusing) then none of the expressions 2 3 or 4 equal the first expression.
write N..I..N..E with the picks
Suppose the number is n, then n/7 - 1 >= 2 Add 1 to both sides: n/7 >= 3 Multiply both sides by 7: n >= 21
Numbers. i^n = i^(n mod 4). With n = 27, 27 mod 4...
n=10/7. i did this one mentally. but are you sure its 8n minus negative 4n or is it 8n minus 4n? 8n- -4n does not equal 8n-4n 8n- -4n is the same as 8n+4n
1 = 1^3 8 = 2^3 27 = 3^3 64 = 4^3 . . . In general the expression would be n^3 for n equal and greater than 1
x to the n divided by x to the n is 1. By the law of powers x to the power n divided by x to the power n is x to the power (n minus n), ie x to the power zero. Things which are equal to the same thing are equal to each other. Therefore x to the power zero = 1. (Unless x = zero!)