7n(n−1)
(n - 4)(n - 12)
It is: 2n^2 -5n -42 equals (2n+7)(n-6) when factored
3x squared minus 25x minus 28
x = ? 42 = x squared minus x
n2 - 100 = (n + 10)(n - 10)
7n(n−1)
It is 2n^3 + 7n^2 - 13n + 3
n squared minus six.
(n - 4)(n - 12)
It is: 2n^2 -5n -42 equals (2n+7)(n-6) when factored
3x squared minus 25x minus 28
2x squared minus 4
n+n-n-n-n+n-n-n squared to the 934892547857284579275348975297384579th power times 567896578239657824623786587346378 minus 36757544.545278789789375894789572356757583775389=n solve for n! the answer is 42
No, unless "a" happens to be equal to 0, or to 1.
x = ? 42 = x squared minus x
-22 - -22