A quadratic expression in the variable x.
2x2 - x - 15 = 0(2x + 5) (x - 3) = 0[2x + 5 = 0] and [x - 3 = 0]x = -5/2 and x = 3{-2.5, 3}
3x^2 + x + 2x^2 = 5x^2 + x
2x^8 x 3x^2 x -4x = -24x^11
2x
A quadratic expression in the variable x.
2x2 - x - 15 = 0(2x + 5) (x - 3) = 0[2x + 5 = 0] and [x - 3 = 0]x = -5/2 and x = 3{-2.5, 3}
Would you mind typing it out for me? I don't quite understand exactly what you are asking. For example, x to the second power minus 4x over x to the second power minus 16 would be... x^2-4x/x^2-16 Do you mind typing it out like that? Because what you wrote makes no sense at all.
The expression 2x^2 times x can be simplified by multiplying the coefficients (2 and 1) to get 2, and adding the exponents of x (2 and 1) to get x^3. Therefore, the simplified expression is 2x^3.
2x2-x-15 = 0 When factorised: (2x+5)(x-3) = 0
x² + x² = 2x²
3x^2 + x + 2x^2 = 5x^2 + x
The power law of indices says: (x^a)^b = x^(ab) = x^(ba) = (x^b)^a → e^(2x) = (e^x)² but e^x = 2 → e^(2x) = (e^x)² = 2² = 4
2x^8 x 3x^2 x -4x = -24x^11
(x^2 - 2x + 2)(x^2 + 2x + 2)
2x3+2x2-12x take out GCF - 2x 2x(x2+x-6) factor - find factors of -6 that add up to 1 2x(x-2)(x+3)
2(x + 2)(x - 2)(x2 + 2x + 4)(x2 - 2x + 4)