The power law of indices says:
(x^a)^b = x^(ab) = x^(ba) = (x^b)^a
→ e^(2x) = (e^x)²
but e^x = 2
→ e^(2x) = (e^x)² = 2² = 4
(2x)2 = 4 x2 Its numerical value depends on the value of 'x'.
find x when, 2x=128 2x=128 /2 /2 x=128 /2 x=64 then check your answer by doing the following if x=64, then what is 2x? 2(64)=? or 2 * 64=? or 2 x 64=? 2 times 64 equals 128!
x=5.54x+1= 2x+12-1 -14x=2x+11-2x -2x2x=11/2 /2x=5.5
2x=5 x=5/2 x=2.5
2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)
7(2 + 2x) is 78 when x = 3. = 5,764,801.
(2x)2 = 4 x2 Its numerical value depends on the value of 'x'.
2 + 2x = 18 2x = 18 - 2 2x = 16 x = 8
It is an equation and the value of x is 2
It equals 2x. For an exact numerical value, multiply the value of x by 2 to get the result.
If 4x-2 equals 2x-34 then x is equal to -16. 4x is equal to 2x-322x is equal to -32x is therefore -16
2x -6 = 4 then 2x = 4 +6 x=10/2 = 5
3x - y = 3y = 2x + 2Put the value of y in the 1st equation:3x - y = 3 it will be -->3x - ( 2x + 2 ) = 33x - 2x - 2 = 3x - 2 = 3X = 5Put the value of X in the 2nd equation so as to find the value of Y :y = 2x + 2y = 2(5) + 2y = 10 + 2Y = 12
5.3 = 2x so x = 5.3/2 = 2.65
x=1y=2x+3y=2*1 + 3y=5
2x + 3 = 6 2x = 3 x = 3/2 = 1.5
y=8 y = 2x y = 2(4) <-- substitute 4 for x y = 8 <-- this is your answer