The answer is 3. How do you find this? List the factors of both 48 and 15: 48: 1,2,3,4,6,8,12,16,24,48 15:1,3,5,15 Then take the greatest common factor, which in this case is 3. :)
15 and 5 both go into every multiple of 15 .
the answer is 11. b = 11 b is unknown value. We need to find out what is "b" to make the statement true. write the given statement 3b + 15 = 48 Subtract 15 from both sides 3b + 15 -15 = 48 - 15 3b = 33 Divide both sides by 3 3b/3 = 33/3 b = 11
Both 15 and 20 can go into 60, as they are both factors of that number.
3 with remainder 3.
The answer is 3. How do you find this? List the factors of both 48 and 15: 48: 1,2,3,4,6,8,12,16,24,48 15:1,3,5,15 Then take the greatest common factor, which in this case is 3. :)
Any Multiple of 24. 24, 48, 72, 96... Etc.. Hope I helped!
Yes, 48 times.
15 and 5 both go into every multiple of 15 .
Let's see if this is true. Assume that their sum is 48. So, x + (x +1) + (x + 2) = 48 3x + 3 = 48 Subtract 3 at both sides; 3x = 45 Divide 3 to both sides; x = 15 x + 1 = 15 + 1 = 16 x + 2 = 15 + 2 = 17 So, 15 + 16 + 17 = 48 Answer: The sum of three consecutive integers such as 15, 16, and 17 is 48.
Both 15 and 20 can go into 60, as they are both factors of that number.
48/90 = 8/15 hour = 32 minutes
3 with remainder 3.
They both go into 90.
3 times, remainder 3
15
divide both by 3 15/48 divide both by 3 5/16