The answer is 3. How do you find this? List the factors of both 48 and 15: 48: 1,2,3,4,6,8,12,16,24,48 15:1,3,5,15 Then take the greatest common factor, which in this case is 3. :)
15 and 5 both go into every multiple of 15 .
the answer is 11. b = 11 b is unknown value. We need to find out what is "b" to make the statement true. write the given statement 3b + 15 = 48 Subtract 15 from both sides 3b + 15 -15 = 48 - 15 3b = 33 Divide both sides by 3 3b/3 = 33/3 b = 11
Both 15 and 20 can go into 60, as they are both factors of that number.
3 with remainder 3.
15 goes into 48 3.2 times.
The answer is 3. How do you find this? List the factors of both 48 and 15: 48: 1,2,3,4,6,8,12,16,24,48 15:1,3,5,15 Then take the greatest common factor, which in this case is 3. :)
Any Multiple of 24. 24, 48, 72, 96... Etc.. Hope I helped!
Yes, 48 times.
15 and 5 both go into every multiple of 15 .
Let's see if this is true. Assume that their sum is 48. So, x + (x +1) + (x + 2) = 48 3x + 3 = 48 Subtract 3 at both sides; 3x = 45 Divide 3 to both sides; x = 15 x + 1 = 15 + 1 = 16 x + 2 = 15 + 2 = 17 So, 15 + 16 + 17 = 48 Answer: The sum of three consecutive integers such as 15, 16, and 17 is 48.
the answer is 11. b = 11 b is unknown value. We need to find out what is "b" to make the statement true. write the given statement 3b + 15 = 48 Subtract 15 from both sides 3b + 15 -15 = 48 - 15 3b = 33 Divide both sides by 3 3b/3 = 33/3 b = 11
Both 15 and 20 can go into 60, as they are both factors of that number.
48/90 = 8/15 hour = 32 minutes
3 with remainder 3.
They both go into 90.
3 times, remainder 3