Let's see if this is true.
Assume that their sum is 48. So,
x + (x +1) + (x + 2) = 48
3x + 3 = 48 Subtract 3 at both sides;
3x = 45 Divide 3 to both sides;
x = 15
x + 1 = 15 + 1 = 16
x + 2 = 15 + 2 = 17 So,
15 + 16 + 17 = 48
Answer: The sum of three consecutive integers such as 15, 16, and 17 is 48.
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There are three quarters in 12...
3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
3x - 5 = 48 So 3x = 53 and x = 53/3 = 17.66...
c = 4, c squared = 16, 3c squared = 48, 48 + 9 = 57.
48